Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, \(C_2H_4+3O_2\rightarrow2CO_2+2H_2O\) ( đk : nhiệt độ )
b, \(C_2H_5OH+CH_3COOH\rightarrow CH_3COOC_2H_5+H_2O\) ( Dk : Nhiệt độ kèm chất xúc tác là H2SO4 đặc )
c, \(2CH_3COOH+Na_2O\rightarrow2CH_3COONa+H_2O\)
d, \(C_6H_6+Br_2\rightarrow C_6H_5Br+HBr\) ( Chất xúc tác là bột Fe )
e, \(2CH_3COOH+Cu\left(OH\right)_2\rightarrow\left(CH_3COO\right)_2Cu+2H_2O\)
f, \(2C_2H_5OH+2Na\rightarrow2C_2H_5ONa+H_2\uparrow\)
g, \(C_6H_{12}O_6+Ag_2O\rightarrow C_6H_{12}O_7+2Ag\) ( đk : khí NH3 )
h, \(C_6H_6+3Cl_2\rightarrow C_6H_6Cl_6\) ( đk : Ánh sáng )
j, \(2CH_3COO+H_2SO_4\rightarrow2CH_2COOH+SO_4\)
l, \(C_2H_6+Cl_2\rightarrow HCl+C_2H_5Cl\) ( DK : AS)
q, \(CH_2=CH_2+Br_2\rightarrow CH_2Br-CH_2Br\)
Zn+2CH3COOH->(CH3COO)2Zn+H2
0,25-------0,5------------------------------0,25
n CH3COOH=\(\dfrac{30}{60}=0,5mol\)
=>m Zn=0,25.65=16,25g
=>VH2=0,25.22,4=5,6l
CH3COOH+C2H5OH->CH3COOC2H5+H2O
1-------------------------------------1
n CH3COOH=1 mol
n C2H5OH=2,17 mol
=>C2H5OH dư
=>m CH3COOC2H5=1.88=88g
=>H=\(\dfrac{55}{88}100=62,5\%\)
1.\(n_{CH_3COOH}=\dfrac{30}{60}=0,5mol\)
\(Zn+2CH_3COOH\rightarrow\left(CH_3COO\right)_2Zn+H_2\)
0,25 0,5 0,25 ( mol )
\(m_{Zn}=0,25.65=16,25g\)
\(V_{H_2}=0,25.22,4=5,6l\)
2.\(n_{CH_3COOH}=\dfrac{60}{60}=1mol\)
\(n_{C_2H_5OH}=\dfrac{100}{46}=2,17mol\)
\(n_{CH_3COOC_2H_5}=\dfrac{55}{88}=0,625mol\)
\(CH_3COOH+C_2H_5OH\rightarrow CH_3COOC_2H_5+H_2O\)
1 2,17 0,625 ( mol )
0,625 0,625 ( mol )
=> H tính théo CH3COOH
\(H=\dfrac{0,625}{1}.100=62,5\%\)
……… + ……… + ……….
\(a.2Zn+O_2\underrightarrow{t^o}2ZnO\\ b.3H_2O+P_2O_5\rightarrow H_3PO_4\\ c.CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\\ d.\text{K}+2S\underrightarrow{t^o}K_2S\\ e.2H_2O\underrightarrow{dpdd}2H_2+O_2\\f.2KClO_3\underrightarrow{t^o}2KCl+3O_2\\ g.Cu+Cl_2\underrightarrow{t^o}CuCl_2 \\ h.KMnO_4\underrightarrow{t^o}K_2MnO_4+MnO_2+O_2\)
Phản ứng cháy: c
Phản ứng phân huỷ:e,f,h
Phản ứng hoá hợp: a,b,d,g
a)
C2H4 + H2O \(\xrightarrow{t^o,xt}\) C2H5OH
C2H5OH + O2 \(\xrightarrow{men\ giấm}\) CH3COOH + H2O
CH3COOH + C2H5OH ⇌ CH3COOC2H5 + H2O
CH3COOC2H5 + KOH → CH3COOK + C2H5OH
b)
(1) 2C2H5OH + 2Na → 2C2H5ONa + H2
(2) 2CH3COOH + Mg → (CH3COO)2Mg + H2
(3) CH3COOC2H5 + NaOH → CH3COONa + C2H5OH
(4) (RCOO)3C3H5 + 3H2O ⇌ 3RCOOH + C3H5(OH)3
CaO + 3C => CaC2 + CO
CaC2 + 2H2O => Ca(OH)2 + C2H2 (axetilen)
3C2H2 => (cacbon hoạt tính, 600oC) C6H6
C6H6 + Br2 => HBr + C6H5Br (brom benzen)
C2H2 + H2 => (to,Pd) C2H4
C2H4 + H2O => (140oC, H2SO4đ) C2H5OH (rượu etylic)
C2H5OH + O2 => (men giấm) H2O + CH3COOH (axit axetic)
CH3COOH + C2H5OH => (to,H2SO4đ, pứ hai chiều) H2O + CH3COOC2H5 (etyl axetat)
n -(CH2-CH2)- => (to,xt,P) -(CH2-CH2)-n
Chị (anh) copy sai đề rồi ạ, mong chị (anh) xem lại đề và giải giúp em ạ.
\(C_6H_{12}O_6\rightarrow^{men\text{r}ượu}_{t^0}2C_2H_5OH+2CO_2\)
\(C_2H_5OH+O_2\rightarrow^{men\text{gi}ấm}CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH\rightarrow^{H_2SO_4đặc}_{t^0}CH_3COOC_2H_5+H_2O\)
\(CH_3COOC_2H_5+H_2O\rightarrow^{H_2SO_4loãng}_{t^0}CH_3COOH+C_2H_5OH\)
\(2CH_3COOH+2Na\rightarrow2CH_3COONa+H_2\)
Câu 3:
a) PTHH: Na2CO3 + 2 CH3COOH -> 2 CH3COONa + H2O + CO2
b) nNa2CO3= (10,6%.106)/106=0,106(mol)
=> nCH3COOH=nCH3COONa= 2.0,106=0,212(mol)
=> mCH3COOH=0,212 . 60=12,72(g)
=> mddCH3COOH=(12,72.100)/12=106(g)
mCH3COONa=0,212 . 82= 17,384(g)
mddCH3COONa= mddNa2CO3 + mddCH3COOH - mCO2= 106+ 106 - 0,106.44=207,336(g)
=> C%ddCH3COONa= (17,384/207,336).100=8,384%
Câu 1 :
Phản ứng với Etilen :
C2H4 + 3O2 \(\xrightarrow{t^o}\) 2CO2 + 2H2O
C2H4 + Cl2 → C2H4Cl2
Phản ứng với rượu etylic :
C2H5OH + 3O2 \(\xrightarrow{t^o}\) 2CO2 + 3H2O
C2H5OH + HCl → C2H5Cl + H2O
Phản ứng với axit axetic :
CH3COOH + 2O2 \(\xrightarrow{t^o}\) 2CO2 + 2H2O
2CH3COOH + Zn → (CH3COO)2Zn + H2
2CH3COOH + BaCO3 → (CH3COO)2Ba + CO2 + H2O
Ca + 2CH3COOH → (CH3COO)2Ca + H2
câu 2
b )2H2O+CaC2\(\rightarrow\)C2H2 +Ca(OH)2
e)C6H12O6\(\rightarrow\)2C2H5OH+2CO2
n)C2H5OH +2Na\(\rightarrow\)2C2H5ONa+H2
CÂU 1
1. \(2CH_3COOH+Zn\rightarrow\left(CH_3COO\right)_2Zn+H_2\)
\(\left(CH_3COO\right)_2Zn+2HCl\rightarrow ZnCl_2+2CH_3COOH\)
2. b) \(2H_2O+CaC_2\rightarrow Ca\left(OH\right)_2+C_2H_2\)
e) \(C_6H_{12}O_6\xrightarrow[30-35^oC]{menruou}2C_2H_5OH+2CO_2\)
h) \(C_2H_5Br+H_2O\rightarrow C_2H_5OH+HBr\)
m) \(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
n) \(C_2H_5OH+Na\rightarrow C_2H_5ONa+\dfrac{1}{2}H_2\)