a+5=b+7=c+10<=>a=b+2=c+5

=>a>b>c

đáp án:  a < b  < c

vd: 

a => 1 + 5 = 6

b =>  1 + 7 = 8

c => 1 + 10 = 11

dễ thấy : a < b < c

\(25-5n=40-15-5n=40-5\left(n+3\right)⋮n+3\)

\(\Leftrightarrow40⋮n+3\)

mà \(n\)nguyên nên 

\(n+3\inƯ\left(40\right)=\left\{-40,-20,-10,-8,-5,-4,-2,-1,1,2,4,5,8,10,20,40\right\}\)

\(\Leftrightarrow n\in\left\{-43,-23,-13,-11,-8,-7,-5,-4,-2,-1,1,2,5,7,17,37\right\}\).

8+2.x=4:4

8+2.x=1

2x=-7

x=-7/2

x³ + 62 = 63

x³ = 63 - 62

x³ = 1

\(\Rightarrow\)x = 1

Vậy x = 1

x^3+62=63

x^3=1

x^3=1^3

x=1

\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\)ĐK : \(x\ne0\)

\(\Leftrightarrow\frac{40}{8x}+\frac{2xy}{8x}=\frac{x}{8x}\Rightarrow2xy+40=x\)

\(\Leftrightarrow2xy-x=-40\Leftrightarrow-x\left(1-2y\right)=-40\Leftrightarrow x\left(1-2y\right)=40\)

bạn tự xét ước nhé, do nó khá dài =))) 

Bạn tham khảo nha :

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Hok tốt

\(\frac{x+1}{2017}+\frac{x+2}{2016}=\frac{x+3}{2015}+\frac{x+4}{2014}\)

\(\Leftrightarrow\frac{x+1}{2017}+1+\frac{x+2}{2016}+1=\frac{x+3}{2015}+1+\frac{x+4}{2014}+1\)

\(\Leftrightarrow\frac{x+2018}{2017}+\frac{x+2018}{2016}-\frac{x+2018}{2015}-\frac{x+2018}{2014}=0\)

\(\Leftrightarrow\left(x+2018\right)\left(\frac{1}{2017}+\frac{1}{2016}-\frac{1}{2015}-\frac{1}{2014}\ne0\right)=0\Leftrightarrow x=-2018\)

4 mũ 4x-4 =16 mũ x+1

x= -10,

x= -4908/625,

x=  -15427/2000

-15427/2000

mik là thằng trả lời đầu tiên nhé !

Ta có: MN+NP=MP

⇒MP=3+5=8 (cm)

I là trung điểm ⇒ MI=1/2 MP

⇒MI=MP/2 =8/2 = 4(cm)

Vậy MI = 8cm

M__________N___I___________________P

(Hình như trên nhé!)