a) (1*3/10-x):(19/10-1-2/5)+4/5=1
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9 tháng 1 2021
Câu 1 :
a, \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}=\frac{2x-1}{3}-\frac{3-x}{4}\)
\(\Leftrightarrow\frac{6x+3}{4}+\frac{3-x}{4}=\frac{2x-1}{3}+\frac{5x+3}{6}\)
\(\Leftrightarrow\frac{5x+6}{4}=\frac{9x+1}{6}\Leftrightarrow\frac{30x+36}{24}=\frac{36x+4}{24}\)
Khử mẫu : \(30x+36=36x+4\Leftrightarrow-6x=-32\Leftrightarrow x=\frac{32}{6}=\frac{16}{3}\)
tương tự
PN
16 tháng 5 2021
\(\frac{19}{4}-\frac{2\left(3x-5\right)}{5}=\frac{3-2x}{10}-\frac{3x-1}{4}\)
\(< =>\frac{19.5}{20}-\frac{8\left(3x-5\right)}{20}=\frac{2\left(3-2x\right)}{20}-\frac{5\left(3x-1\right)}{20}\)
\(< =>95-24x+40=6-4x-15x+5\)
\(< =>-24x+135=-19x+11\)
\(< =>5x=135-11=124\)
\(< =>x=\frac{124}{5}\)
HN
14 tháng 6 2021
\(\left(1-\frac{3}{10}-x\right):\left(\frac{19}{10}-1-\frac{2}{5}\right)+\frac{4}{5}=1\)
\(\Rightarrow\left(\frac{7}{10}-x\right):\frac{1}{2}=\frac{1}{5}\\ \frac{7}{10}-x=\frac{1}{5}.\frac{1}{2}\\ \frac{7}{10}-x=\frac{1}{10}\\ \Rightarrow x=\frac{7}{10}-\frac{1}{10}=\frac{3}{5}\)
TN
26 tháng 6 2016
\(\left(1-\frac{3}{10}-x\right):\left(\frac{19}{10}-1-\frac{2}{5}\right)+\frac{4}{5}=1\)
\(\Rightarrow\left(\frac{7}{10}-x\right):\frac{1}{2}+\frac{4}{5}=1\)
\(\Rightarrow\left(\frac{7}{10}-x\right):\frac{1}{2}=\frac{1}{5}\)
\(\Rightarrow\frac{7}{10}-x=\frac{1}{10}\)
\(\Rightarrow x=\frac{3}{5}\)
LM
Lê Minh Vũ
VIP
15 tháng 6 2023
3 x 15 + 21 x 15 + 85 x 5
= 45 + 315 + 425
= 785
15 - 30 + 40
= 25
21 + 19 - 50 + 10
= 0
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=-\dfrac{1}{20}+2\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{12}\times\dfrac{3}{12}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=-\dfrac{9}{20}\)
BD
15 tháng 6 2023
\(3\times15+21\times15+85\times5\\ =15\times\left(3+21\right)+425\\ =15\times24+425\\ =360+425\\ =785\)
\(15-30+40\\ =\left(15+40\right)-30\\ =55-30\\ =25\)
\(21+19-50+10\\ =\left(21+19\right)-\left(50-10\right)\\ =40-40\\ =0\)
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=\dfrac{4}{20}-\dfrac{5}{20}+\dfrac{40}{20}\)
\(=\dfrac{\left(4+40\right)}{20}-\dfrac{5}{20}\)
\(=\dfrac{44}{20}-\dfrac{5}{20}\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=\dfrac{2}{20}+\dfrac{4}{20}-\dfrac{15}{20}\)
\(=\dfrac{6}{20}-\dfrac{15}{20}\)
\(=-\dfrac{9}{20}\)
19 tháng 9 2023
\(1\dfrac{1}{6}+1\dfrac{1}{4}=\dfrac{7}{6}+\dfrac{5}{4}=\dfrac{14}{12}+\dfrac{15}{12}=\dfrac{14+15}{12}=\dfrac{19}{12}=1\dfrac{7}{12}\)\(2\dfrac{2}{3}\div1\dfrac{3}{19}=\dfrac{8}{3}\div\dfrac{22}{19}=\dfrac{8}{3}\times\dfrac{19}{22}=\dfrac{8\times19}{3\times22}=\dfrac{76}{33}\)
TN
14 tháng 12 2023
tìm x:
a)x=5/8-1/4
x=5/8-2/8
x=3/8
b)x=1/10+3/5
x=1/10+3/10
x=4//10
c) x = 7/8 - 1/4
x = 5/8
d)x=1/4x3/2
x=3/8
đ) X = 6/11 : 2/7
X =6/11x7/2
X= 21/11
e)X=4/5:2/3
X=4/5x3/2
X=12/10=6/5
tính
a) 7/9 x 5/6=35/54
b) 1/5 : 7/10=1/5x10/7
=10/35=2/7
c) 6/5 x ( 2/3 - 3/5 )=6/5x(9/15-10/15)
=6/5x3/5
=18/25
d) 1/4 : 3/8 x 6/5=1/4x8/3x6/5
=2/3x6/5
=12/15=4/5
không biết có đúng không nhưng đúng nhớ tick cho mình nha,mình cảm ơnn
NT
1
KN
22 tháng 7 2015
a) => (35:x+3)*15 = 165-15=150
=> 35:x+3 = 150:15=10
=> 35:x = 10-3 = 7
=> x = 35:7 = 5
b) => 1*3/10x :1/2 +4/5 =1
=> 1*3/10x:1/2 =1-4/5=1/5
=> 1*3/10x = 1/5 *1/2 =1/10
=> 3/10-x = 1/10
=> x = 3/10 - 1/10 = 2/10 = 1/5
HN
28 tháng 8 2021
a,
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)
\(\Rightarrow5^{x+3}2=2.5^{11}\)
\(\Rightarrow5^{x+3}=5^{11}\)
\(\Rightarrow x+3=11\)
\(\Rightarrow x=8\)
HN
28 tháng 8 2021
b, (Check lai xem de sai o dau khong nhe)
\(3.5^{x+2}+4.5^{x+3}=19.5^{10}\)
Dat 5x ra ben ngoai
\(\Rightarrow5^x.5^23+5^x:5^{-3}.4\)
\(\Rightarrow5^x\left(5^2.3+5^{-3}.4\right)\)
\(\Rightarrow5^x\left(5^{-3}.5^5.3+5^{-3}.4\right)\)
\(\Rightarrow5^x[5^{-3}\left(5^53+4\right)\)
\(\Rightarrow5^x[5^{-3}\left(3125.3+4\right)\)
\(\Rightarrow5^x\left(5^{-3}\right).9379\)
=> Khong tim duoc gia tri cua x \(\Rightarrow x\in\varnothing\)