-152=(3x+1)=(-2)-x
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![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(\left(5x-1\right)\left(5x+1\right)=25x^2-7x+15\)
\(\Leftrightarrow25x^2-1=25x^2-7x+15\)
\(\Leftrightarrow7x=16\Leftrightarrow x=\dfrac{16}{7}\)
2) \(\left(3x-5\right)\left(x+1\right)-\left(3x-1\right)\left(x+1\right)=x-4\)
\(\Leftrightarrow3x^2-2x-5-3x^2-2x+1=x-4\)
\(\Leftrightarrow5x=0\Leftrightarrow x=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Trl:
a) \(x+x+x+91=-2\)
\(\Rightarrow x.3+91=-2\)
\(\Rightarrow x.3=-2-91\)
\(\Rightarrow x.3=-93\)
\(\Rightarrow x=-93:3\)
\(\Rightarrow x=-31\)
b) \(-125-\left(3x+1\right)=-2.27\)
\(\Rightarrow-125-\left(3x+1\right)=-54\)
\(\Rightarrow\left(3x+1\right)=-125-\left(-54\right)\)
\(\Rightarrow\left(3x+1\right)=-125+54\)
\(\Rightarrow\left(3x+1\right)=-71\)
\(\Rightarrow3x=-71-1\)
\(\Rightarrow3x=-72\)
\(\Rightarrow x=-72:3\)
\(\Rightarrow x=-24\)
Hc tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5(-x - 2) = 0
-x - 2 = 0
-x = 0 + 2
-x = 2
x = -2 (nhận)
Vậy x = -2
b) (-4).x = 26
x = 26 : (-4)
x = -13/2 (loại)
Vậy không tìm được x là số nguyên thỏa mãn đề bài
c) -152 - (3x + 1) = (-2).27
-152 - (3x + 1) = -54
3x + 1 = -152 + 54
3x + 1 = -98
3x = -98 - 1
3x = -99
x = -99 : 3
x = -33 (nhận)
Vậy x = -33
![](https://rs.olm.vn/images/avt/0.png?1311)
-152-(3x+1)=-2.(-77)
-152-(3x+1)=154
3x+1 = 154 + 152
3x + 1 = 306
3x = 306 - 1
3x = 305
x = \(\frac{305}{3}\)
Trả lời :
- 152 - ( 3x + 1 ) = - 2 . ( - 77 )
- 152 - ( 3x + 1 ) = 154
=> 3x - 1 = ( - 152 ) - 154
=> 3x - 1 = - 306
3x = - 306 + 1
3x = - 305
=> x = - 305 : 3
x = \(\frac{-305}{3}\)
Vậy x = \(\frac{-305}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x + x + x + 91 = -2
x + x + x = -2 - 91
x + x + x = -93
3x = -93
x = -93 : 3
x = -31
-152 - (3x + 1) = (-2) . (-27)
-152 - (3x + 1) = 54
3x + 1 = -152 - 54
3x + 1 = -206
3x = -206 - 1
3x = -207
x = -207 : 3
x = -69
|5x + 1| = 11
5x + 1 = 11 hay 5x + 1 = -11
5x = 11 - 1 hay 5x = -11 - 1
5x = 10 hay 5x = -12
x = 10 : 5 hay x = -12 : 5
x = 2 hay x = -2,4
Mà x ∈ Z
x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
n: (-8)*x+17=-23
=>\(x\cdot\left(-8\right)=-23-17=-40\)
=>\(x\cdot8=40\)
=>\(x=\dfrac{40}{8}=5\)
o: \(\left(-15\right)\cdot x=10\left(-4\right)-5\)
=>\(x\cdot\left(-15\right)=-40-5=-45\)
=>\(x\cdot15=45\)
=>\(x=\dfrac{45}{15}=3\)
p: \(\left(-3\right)\cdot x-4=2\cdot\left(-7\right)+4\)
=>\(\left(-3\right)\cdot x-4=-14+4=-10\)
=>\(x\left(-3\right)=-10+4=-6\)
=>\(3x=6\)
=>\(x=\dfrac{6}{3}=2\)
q: x+x+x+91=-2
=>\(3x+91=-2\)
=>\(3x=-2-91=-93\)
=>\(x=-\dfrac{93}{3}=-31\)
r: \(-152-\left(3x+1\right)=\left(-2\right)\cdot\left(-27\right)\)
=>\(-152-3x-1=54\)
=>\(-153-3x=54\)
=>\(3x=-153-54=-207\)
=>\(x=-\dfrac{207}{3}=-69\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\Leftrightarrow\left(2x-5\right)^3=225-4\cdot100=125\)
=>2x-5=5
=>2x=10
hay x=5
b: \(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)
hay \(x\in\left\{2;5\right\}\)
c: =>x-5-2x-7=-8
=>-x-12=-8
=>x+12=8
hay x=-4
![](https://rs.olm.vn/images/avt/0.png?1311)
( - 152 ) - ( 3x+1 ) = (-2) . (-77)
(- 152 ) - (3x +1 ) = 154
3x +1 = (-152)- 154
3x + 1 = -306
3x = - 306 - 1
3x = - 307
x = - 307 : 3
x = - 307 / 3 ( dấu / là chỉ phân số)
#hoang hai yen :
đề bài là j zậy bn
tìm x à
bằng -51 hoặc 150 nha bn