-25 - ( x + 5 ) = 145 + 5. ( x + 85)
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Ta có: \(\dfrac{x-25}{75}+\dfrac{x-15}{85}+\dfrac{x-5}{95}+\dfrac{x-145}{15}=0\)
\(\Leftrightarrow\dfrac{x-25}{75}-1+\dfrac{x-15}{85}-1+\dfrac{x-5}{95}-1+\dfrac{x-145}{15}+3=0\)
\(\Leftrightarrow\dfrac{x-100}{75}+\dfrac{x-100}{85}+\dfrac{x-100}{95}+\dfrac{x-100}{15}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{75}+\dfrac{1}{85}+\dfrac{1}{95}+\dfrac{1}{15}\right)=0\)
mà \(\dfrac{1}{75}+\dfrac{1}{85}+\dfrac{1}{95}+\dfrac{1}{15}>0\)
nên x-100=0
hay x=100
Vậy: S={100}
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a)
x × 1 1 2 = 1 4 5 − 2 5 x × 3 2 = 9 5 − 2 5 x × 3 2 = 7 5 x = 7 5 : 3 2 x = 14 15
b)
x × 0 , 75 + x × 0 , 25 = 5 x × 0 , 75 + 0 , 25 = 5 x × 1 = 5 x = 5 : 1 x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
`x + 25 = 5/6 (85 - x)`
`=> x + 25 =425/6 - (5x)/6`
`=> x + (5x)/6=425/6-25`
`=> 11x/6 = 275/6`
`=> 11x=275`
`=>x= 275:11`
`=>x= 25`
![](https://rs.olm.vn/images/avt/0.png?1311)
Trả lời:
\(194-24\div\left(44x-3\right)-25=145\)
\(\Leftrightarrow194-24\div\left(44x-3\right)=170\)
\(\Leftrightarrow24\div\left(44x-3\right)=24\)
\(\Leftrightarrow44x-3=1\)
\(\Leftrightarrow44x=4\)
\(\Leftrightarrow x=\frac{1}{11}\)
Vậy \(x=\frac{1}{11}\)
\(x\times\frac{1}{3}\div\frac{2}{9}-x\div5=1\frac{2}{5}\)
\(\Leftrightarrow x\times\frac{1}{3}\times\frac{9}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{3}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\left(\frac{3}{2}-\frac{1}{5}\right)=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{13}{10}=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{14}{13}\)
Vậy \(x=\frac{14}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) đề bài => \(\frac{159-x}{141}+1+\frac{157-x}{143}+1+...+\frac{151-x}{149}+1=0\)
=>\(\frac{300-x}{141}+\frac{300-x}{143}+...+\frac{300-x}{149}=0\)
=>\(\left(300-x\right).\left(\frac{1}{141}+\frac{1}{143}+...+\frac{1}{149}\right)=0\)
vì \(\frac{1}{141}+\frac{1}{143}+...+\frac{1}{149}\ne0\)
=> \(300-x=0\)
=>\(x=300\)
chờ mình chút sẽ có câu b. k cho mình nha.
![](https://rs.olm.vn/images/avt/0.png?1311)
5/2+13/6+25/12+41/20+61/30+85/42
=2+1/2+2+1/6+2+1/12+2+1/20+2+1/30+2+1/42
=12+(1/2+1/6+1/12+1/20+1/30+1/42)
=12+(1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7)
=12+(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7)
=12+1-1/7
=90/7
5/2+13/6+25/12+41/20+61/30+85/42
=2+1/2+2+1/6+2+1/12+2+1/20+2+1/30+2+1/42
=12+(1/2+1/6+1/12+1/20+1/30+1/42)
=12+(1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7)
=12+(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7)
=12+1-1/7
=90/7
![](https://rs.olm.vn/images/avt/0.png?1311)
( x - 25) x 17 = 34
=> x - 25 = 34 : 17
x - 25 = 2
=> x = 2 + 25
x = 27
145 + (150 - x) = 250
=> 150 - x = 250 - 145
150 - x = 105
=> x = 150 - 105
x = 45
(2x - 7) x 81 = 0
=> 2x - 7 = 0 : 81
2x - 7 = 0
=> 2x = 7
=> x = 7 : 2 = 3,5
x - 90 : 15 = 32
=> x - 6 = 32
=> x = 32 + 6
x = 38
520 - (x - 5) = 250 : 5
=> 520 - (x - 5) = 50
=> x - 5 = 520 - 50
x - 5 = 470
=> x = 470 + 5
x = 475
t i c k nhé!! 346457567684786896789
a ) \(\left(x-5\right).17=34\)
=> \(x-5=2\)
=> \(x=7\)
b ) \(145+\left(150-x\right)=250\)
=> \(150-x=105\)
=> \(x=150-105\)
=> \(x=45\)
c ) \(\left(2.x-7\right).81=0\)
=> \(2x-7=0\)
=> \(2x=7\)
=> \(x=\frac{7}{2}\)
d ) \(x-90:15=32\)
=> \(x-6=32\)
=> \(x=38\)
Mấy cái dấu chấm đó là nhân đó nhé
\(-25-\left(x+5\right)=145+5\left(x+85\right)\)
\(-25-x-5=145+5x+425\)
\(-x-5x=570+25+5\)
\(-6x=600\)
\(x=-100\)
vậy \(x=-100\)