cho tam giác ABC cân tại A lấy 1 điểm D trên tia đối của tia CA lấy 1 điểm E sao cho BD=CE.Đường thẳng DE cắt BC ở F. Chứng minh DF=EF
K
Khách
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Những câu hỏi liên quan
27 tháng 7 2023
a: góc FEB+góc FBE=45+45=90 độ
=>EF vuông góc BC
b: ΔDFC vuông tại F có góc C=45 độ
nên ΔDFC vuông cân tại F
=>FD=FC
c: Xét ΔBEC có
EF,CA là đường cao
EF cắt CA tại D
=>D là trực tâm
=>BD vuông góc CE
24 tháng 2 2019
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1 tháng 3 2019
xin lỗi mk ko bt giải vì chưa ok
ai như vậy thì k mk nha
cái nịt