cho hàm số y = f(x) = 2x - 5 . tính f(o) . f(-1)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
y=f(-1)=3*(-1)-2=-5
y=f(0)=3*0-2=-2
y=f(-2)=3*(-2)-2=-8
y=f(3)=3*3-2=7
Câu 2,3a làm tương tự,chỉ việc thay f(x) thôi.
3b
Khi y=5 =>5=5-2*x=>2*x=0=> x=0
Khi y=3=>3=5-2*x=>2*x=2=>x=1
Khi y=-1=>-1=5-2*x=>2*x=6=>x=3
f(-1)=3.1-2=3-2=1
f(0)=3.0-2=0-2=-2
f(-2)=3.(-2)-2=-6-2=-8
f(3)=3.3-2=9-2=7
![](https://rs.olm.vn/images/avt/0.png?1311)
F(-2) = 5 -2.(-2) = 5 + 4 =9
F(-1) =5 – 2.(-1) = 5 + 2 = 7
F(0) = 5 – 2.0 = 5
F(3) = 5 – 2.3 = 5 – 6 =-1
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
f(0) = 1/2.0 + 5 = 5
f(2) = 1/2.2 + 5 = 6
f(3) = 1/2.3 + 5 = 13/2
f(-2) = 1/2.(-2) + 5 = 4
f(-10) = 1/2.(-10) + 5 = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
f(0) = 1/2.0 + 5 = 5
f(2) = 1/2.2 + 5 = 6
f(3) = 1/2.3 + 5 = 13/2
f(-2) = 1/2.(-2) + 5 = 4
f(-10) = 1/2.(-10) + 5 = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
a: f(0)=5
f(-1)=2+5=7
f(1)=-2+5=3
f(-2)=4+5=9
f(1/2)=-1+5=4
f(-1/2)=2+5=7
b: Khi y=5 thì -2x+5=5
=>x=0
Khi y=-3 thì -2x+5=-3
=>-2x=-8
hay x=4
Khi y=19 thì -2x+5=19
=>-2x=14
hay x=-7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(f\left(3\right)=\left|\dfrac{3}{2}\cdot3-\dfrac{5}{2}\right|=2\)
\(f\left(-3\right)=\left|\dfrac{3}{2}\cdot\left(-3\right)-\dfrac{5}{2}\right|=7\)
\(f\left(\dfrac{1}{2}\right)=\left|\dfrac{3}{2}\cdot\dfrac{1}{2}-\dfrac{5}{2}\right|=\dfrac{7}{4}\)
\(f\left(-\dfrac{1}{2}\right)=\left|\dfrac{3}{2}\cdot\dfrac{-1}{2}-\dfrac{5}{2}\right|=\dfrac{13}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(f\left(2\right)=3\cdot2^3-2\cdot2^2+5=21\)
\(f\left(1\right)=3\cdot1^3-2\cdot1^2+5=3-2+5=6\)
\(f\left(-3\right)=3\cdot\left(-3\right)^3-2\cdot\left(-3\right)^2+5=3\cdot\left(-27\right)-2\cdot9+5=-94\)
Ta có
\(f\left(2\right)=3.8-2.4+5=24-3=21\)
\(f\left(1\right)=3-2+5=6\)
\(f\left(-3\right)=3.\left(-27\right)-2.9+5=-81-18+5=-94\)
`y = f(x) = 2x - 5`
`f(0) = 2 . 0 - 5 = -5`
`f(-1) = 2 . (-1) - 5 = -2 - 5 = -7`
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