`{(38/x + 64/y = 3),(19/x + 16/y = 1):}`
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18 x 38 + 16 x 76 -1 = ( 36 x 19 + 64 x 20 - 65 ) x X
( 36x 19 + 64 x 20 - 65 ) x X = 18x 38 + 16x 76 -1
1899 x X = 1899
X = 1899 / 1899
X = 1
18x38+16x76-1=[36x19+64x20-65]xX
[36x19+64x20-65]xX=18x38+16x76-1
1899xX=1899
x=1899/1899
x=1
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(18+38+16*76-1)=(36*19+64*20-65)-x
=>(18+38+1216-1)=(684+1280-65)-x
=>1271=1899-x
=>1899-x=1271
x = 1899-1271
x=628
vậy x= 628
( 18 + 38 + 1216 - 1) = ( 684 +1280 - 65) - x
( 56 + 1216 - 1) = ( 1964 - 65) - x
1271 = 1899 - x
x = 1899 - 1271
x = 628
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2. Tham khảo thêm tại đây nha bạn
https://hoc24.vn/hoi-dap/question/417550.html
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(dấu chấm là dấu nhân nha e)
*\(\dfrac{1}{2}\). \(\dfrac{1}{4}\)+\(\dfrac{3}{4}\)
= \(\dfrac{1}{8}\)+\(\dfrac{3}{4}\)
= \(\dfrac{1}{8}\)+\(\dfrac{6}{8}\)= \(\dfrac{7}{8}\)
*\(\dfrac{3}{4}\).\(\dfrac{5}{6}\).\(\dfrac{8}{15}\)
= \(\left(\dfrac{3}{4}.\dfrac{8}{15}\right)\).\(\dfrac{5}{6}\)
= \(\dfrac{2}{5}\).\(\dfrac{5}{6}\)
= \(\dfrac{1}{3}\)
*\(\dfrac{12}{19}\): \(\dfrac{17}{38}\).\(\dfrac{16}{9}\)
= \(\dfrac{12}{19}\). \(\dfrac{38}{17}\).\(\dfrac{16}{9}\)= 2,5
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ĐKXĐ: x<>0 và y<>0
\(\left\{{}\begin{matrix}\dfrac{38}{x}+\dfrac{64}{y}=3\\\dfrac{19}{x}+\dfrac{16}{y}=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{38}{x}+\dfrac{64}{y}=3\\\dfrac{38}{x}+\dfrac{32}{y}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{32}{y}=1\\\dfrac{19}{x}+\dfrac{16}{y}=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=32\\\dfrac{19}{x}=1-\dfrac{16}{32}=\dfrac{1}{2}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=32\\x=38\end{matrix}\right.\left(nhận\right)\)