Question

[Nguyễn Thị Gia Hân]

câu 1 làm từ câu i cũng được ạ
xin mng cứu em D:

Answer 1

[Nguyễn Lê Phước Thịnh]

1:

i: \(=\dfrac{15}{34}+\dfrac{19}{34}+\dfrac{7}{21}+\dfrac{2}{3}-1-\dfrac{15}{37}\)

\(=1+\dfrac{1}{3}+\dfrac{2}{3}-1-\dfrac{15}{37}\)

\(=1-\dfrac{15}{37}=\dfrac{22}{37}\)

j: \(=1-\left(-27\right)+\dfrac{1}{2}:\dfrac{-1}{8}\)

\(=1+27-4=24\)

k: \(=-8+\dfrac{1}{2}\cdot\dfrac{-4}{1}-15\)

\(=-8-2-15=-25\)

l: \(=3:\dfrac{9}{4}+\dfrac{1}{9}\cdot6\)

\(=3\cdot\dfrac{4}{9}+\dfrac{1}{9}\cdot6\)

\(=\dfrac{4}{3}+\dfrac{2}{3}=2\)

m: \(=9\cdot\dfrac{1}{3}-\left(-27\right)=3+27=30\)

n: \(\sqrt{\dfrac{16}{25}}\cdot\sqrt{\dfrac{121}{64}}-1\dfrac{3}{10}\)

\(=\dfrac{4}{5}\cdot\dfrac{11}{8}-\dfrac{13}{10}\)

\(=\dfrac{11}{10}-\dfrac{13}{10}=-\dfrac{2}{10}=-\dfrac{1}{5}\)

o: \(=\dfrac{9}{8}\cdot12-\dfrac{1}{2}\)

\(=\dfrac{27}{2}-\dfrac{1}{2}=\dfrac{26}{2}=13\)

p: \(=\dfrac{3^2\cdot2^2+3^2\cdot3\cdot2^2+3^2}{-13}\)

\(=\dfrac{3^2\left(2^2+3\cdot2^2+3^2\right)}{-13}\)

\(=\dfrac{9\cdot\left(4+3\cdot4+9\right)}{-13}\)

\(=\dfrac{9\cdot25}{-13}=-\dfrac{225}{13}\)