Cho mình hoi (5392+6001*5931) /5932*6001-69 phân. Tích mẫu còn bài này thi phân tích tử 402*123-180/ 201*121+111 tăng tốc lam giúp minh nhe 🚄 🚄 🚄 thanh các ban nhiều tang tóc lên nhé
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Gọi số cần tìm là a
Ta thấy:
Khi đem tử số của phân số đã cho trừ đi số đó và đem mẫu số của phân số đã cho cộng với số đó thì tổng giữa tử số và mẫu số của phân số đó ko thay đổi.
Tổng giữa mẫu số và tử số của phân số 15/17 là :
17+15=32
Tổng giữa mẫu số và tử số của phân số 1/3 là :
3+1=4
Phân số 1/3 bị rút gọn số lần là :
32:4=8
Phân số 1/3 khi chưa rút gọn là :
1x8/3x8=8/24
Vậy số cần tìm là :
15‐8=7 ﴾ hoặc 24‐ 17=7﴿
Đáp số :7
các bạn tk mình nhé
15-a/17+a=1/3
suy ra nhan cheo hang tu ta co
45-3a=17+a
28=4a
a=7
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5932+6001:5931x5932:6001- 69
= 5932 x ( 5931+ 69 ) : 6001 : 6001
= 5932 x 6000 : 1
= 35 592 000
k mình nha
\(\frac{5932+6001.5931}{5932.6001-69}\)
= \(\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)
=\(\frac{5932+6001.5931}{5931.6001+6001-69}\)
=\(\frac{5932+6001.5931}{5931.6001.5031}\)= 1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5392+6001x5931}{6381x6001-69}=\frac{35597323}{3829312}\)
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\(\dfrac{5932+6001x5931}{5932x600-69}=\dfrac{5932+6001x\left(5932-1\right)}{5932x6001-69}=\dfrac{5932+6001x5932-6001}{5932x6001-69}=\dfrac{5932x6001-\left(6001-5932\right)}{5932x6001-69}=\dfrac{5932x6001-69}{5932x6001-69}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5932+6001.5931}{5932.6001-69}=\frac{6001.5931+5932}{5931.6001+6001-69}=\frac{6001.5931+5932}{6001.5931+5932}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\dfrac{5931+6001\cdot5931+1}{5931\cdot6001+6001-69}\)
\(=\dfrac{5931\cdot6001+5932}{5931\cdot6001+5932}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5931\times6001+5932}=1\)