\(\sqrt{15-\sqrt{216}+\sqrt{33-12\sqrt{6}}}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2\sqrt{15-\sqrt{216}}+\sqrt{33-12\sqrt{6}}\)
\(=2\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=2\sqrt{9-6\sqrt{6}+6}+\sqrt{24-12\sqrt{6}+9}\)
\(=2\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}-3\right)^2}\)
\(=2\left|3-\sqrt{6}\right|+\left|2\sqrt{6}-3\right|\)
\(=6-2\sqrt{6}+2\sqrt{6}-3\)
\(=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{15-6\sqrt{6}}\)\(+\sqrt{33-12\sqrt{6}}\)=\(\sqrt{3^2-2\cdot3\cdot\sqrt{6}+\left(\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}\right)^2-2\cdot3\cdot2\sqrt{6}+3^2}\) =\(\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}-3\right)^2}=3-\sqrt{6}+2\sqrt{6}-3=\sqrt{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}-3\right)^2}\)
\(=3-\sqrt{6}+2\sqrt{6}-3\)
\(=\sqrt{6}\)
\(\sqrt{15-\sqrt{216}}\)+\(\sqrt{33-12\sqrt{6}}\)
=\(\sqrt{9-2.3.\sqrt{6}+6}\)+\(\sqrt{24-2.3.2.\sqrt{6}+9}\)
=\(\sqrt{\left(3-\sqrt{6}\right)^2}\)+\(\sqrt{\left(2\sqrt{6}-3\right)^2}\)
=/3-√6/+/2√6-3/
=3-\(\sqrt{6}\)+2\(\sqrt{6}\) -3=\(\sqrt{6}\) CHÚC BẠN THÀNH CÔNG
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{15-\sqrt{216}}+\sqrt{33-12\sqrt{6}}=\sqrt{6-6\sqrt{6}+9}+\sqrt{24-12\sqrt{6}+9}=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(\sqrt{24}-3\right)^2}=\left|3-\sqrt{6}\right|+\left|\sqrt{24}-3\right|=3-\sqrt{6}+\sqrt{24}-3=2\sqrt{6}-\sqrt{6}=\sqrt{6}\)
\(\dfrac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}=-\dfrac{\sqrt{2}\left(\sqrt{6}-4\right)}{\sqrt{3}\left(\sqrt{6}-4\right)}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{6}\left(\sqrt{5}+\sqrt{27}\right)}=\dfrac{-\sqrt{2}}{\sqrt{3}}-\dfrac{1}{\sqrt{6}}=\dfrac{-\sqrt{6}}{3}-\dfrac{\sqrt{6}}{6}=-\dfrac{\sqrt{6}}{2}\).
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{15-2.3.\sqrt{6}}+\sqrt{33-2.6\sqrt{6}}\)
\(=\sqrt{3^2-2.3.\sqrt{6}+\sqrt{6^2}}+\sqrt{24-2.2\sqrt{6}.3+9}\)
\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}-3\right)^2}\)
\(=\left(3-\sqrt{6}\right)-\left(2\sqrt{6}-3\right)\)
\(=3-\sqrt{6}-2\sqrt{6}+3\)
\(=6-3\sqrt{6}\)
Ko vt lại đề nha bn:
\(=\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{15-2.3.\sqrt{6}}+\sqrt{33-2.6\sqrt{6}}\)
\(=\sqrt{3^2-2.3.\sqrt{6}+\sqrt{6^2}}+\sqrt{24-2.2\sqrt{6}.3+9}\)
\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}-3\right)^2}\)
\(=\left(3-\sqrt{6}\right)-\left(2\sqrt{6}-3\right)\)
\(=3-\sqrt{6}-2\sqrt{6}+3\)
\(=6-3\sqrt{6}\)
Rất vui vì giúp đc bn !!!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\sqrt{15-\sqrt{216}}+\sqrt{33-12\sqrt{6}}=\sqrt{9-2.3\sqrt{6}+6}+\sqrt{24-2.2\sqrt{6}.3+9}=3-\sqrt{6}+2\sqrt{6}-3=\sqrt{6}\) \(b.2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}=8\sqrt{\dfrac{1}{3}}-\sqrt{\dfrac{1}{3}}-\dfrac{12}{5}\sqrt{\dfrac{1}{3}}=\dfrac{23}{5}\sqrt{\dfrac{1}{3}}\)
yêu cầu ?
= 2 căn 6 - 3 + 3 - căn 6
= căn 6
Cho mình xin 1 tick nha trang