1/2 +1/14+1/35+...+1/104+1/152. mọi ng giải thick cụ thể cho mình vs ạ.
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{1}{65}+\frac{1}{104}+\frac{1}{152}\)
\(=\frac{1}{1.2}+\frac{1}{2.7}+\frac{1}{7.5}+\frac{1}{5.13}+\frac{1}{13.8}+\frac{1}{8.19}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{5}+\frac{1}{5}-\frac{1}{13}+\frac{1}{13}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}\)
\(=1-\frac{1}{19}\)
\(=\frac{18}{19}\)
~Học tốt~
\(\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{1}{65}+\frac{1}{104}+\frac{1}{152}\)
\(=\frac{1}{2}+\frac{1}{2.7}+\frac{1}{7.5}+\frac{1}{5.13}+\frac{1}{13.8}+\frac{1}{8.19}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{5}+\frac{1}{5}-\frac{1}{13}+\frac{1}{13}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}\)
\(=1-\frac{1}{19}\)
\(=\frac{18}{19}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Em check lại đề anh nghĩ phân số mới là 2/5 mới đúng cơ
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{1}{3}+\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}\cdot\dfrac{6}{5}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}\)
\(x=\dfrac{27}{10}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}:\dfrac{5}{6}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}=\dfrac{27}{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta đặt
\(A=\dfrac{1}{2}+\dfrac{1}{14}+\dfrac{1}{35}+....+\dfrac{1}{152}\)
\(A=\dfrac{2}{4}+\dfrac{2}{28}+....+\dfrac{2}{304}\)
\(A=\dfrac{2}{1\times4}+\dfrac{2}{4\times7}+....+\dfrac{2}{16\times19}\)
\(\dfrac{3}{2}A=\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+....+\dfrac{3}{16\times19}\)
\(\dfrac{3}{2}A=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+....+\dfrac{1}{16}-\dfrac{1}{19}\)
\(\dfrac{3}{2}A=1-\dfrac{1}{19}=\dfrac{18}{19}\)
\(A=\dfrac{18}{19}\div\dfrac{3}{2}\)
\(A=\dfrac{12}{19}\)