giúp mình 3 bài trên với ạ! mình cảm ơn
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bn có thể tham khảo trên vietjack á, đầy đủ chi tiết lắm :v
(* tại mik ko muốn tham khảo thôi :>)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Gọi x,y,z là số học sinh khối 6, 7, 8
(x,y,z>0, đvị là học sinh)
Đã biết khối học sinh lớp 8 ít hơn số hs khối 6 là 120 hs
x-z=120
x, y, z tỉ lệ với 8, 7, 5
x/8=y/7=z/5
Áp dụng tính chất dãy tỉ số bằng nhau có:
x/8=y/7=z/5= x-z/8-5=120/3=40
=> x/8= 40 => x=40.8=320 => số hs khối 6 là 320 hs
y/7= 40 y=40.7= 280 số hs khối 7 là 280 hs
z/5= 40 z=40.5=200 số hs khối 8 là 200 hs
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bài IX:
1. no sooner returned from his walk than he got down to writing
2. Hard as he worked, he failed
3. you keep calm, you will pass
4. apologized for going to
5. the song without any
6. em làm đúng rồi
7. it hard to translate this poem
8. had such a fierce dog that nobody dared to enter
9. Hoa nor her brother answered my
10. my clothes to be ironed by my younger sister
bài VIII:
1. I didn't have enough time to go back home for my umbrella.
2. Your cat needed to be looked after properly.
3. There weren't any gifts for me, were they?
4. If only I had studied harder at school.
5. Would you mind coming and collecting me from the station?
6. The harder you work, the more success you get.
7. Minh was not allowed to go out at night by Mr. Ba.
8. You must have been proud of your son's success.
9. I have moved to the construction company for 3 years.
10. The football players are still training.
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Bài 1:
a, \(\)\(\)\(=>R2//\left[R4nt\left(R3//R5\right)\right]\)
\(=>Rtd=\dfrac{R2\left[R4+\dfrac{R3.R5}{R3+R5}\right]}{R2+R4+\dfrac{R3.R5}{R3+R5}}=\dfrac{1.\left[1+\dfrac{1}{1+1}\right]}{1+1+\dfrac{1}{1+1}}=0,6\left(ôm\right)\)
\(=>I=\dfrac{Uab}{Rtd}=\dfrac{10}{0,6}=\dfrac{50}{3}A=I1\)
\(=>Uab=U2345=10V=U2=U345\)
\(=>I2=\dfrac{U2}{R2}=\dfrac{10}{1}=10A\)
\(=>I345=\dfrac{U345}{R345}=\dfrac{10}{1+\dfrac{1.1}{1+1}}=\dfrac{20}{3}A=I4=I35\)
\(=>U35=I35.R35=\dfrac{20}{3}.\dfrac{1.1}{1+1}=\dfrac{10}{3}V=U3=U5\)
\(=>I3=\dfrac{U3}{R3}=\dfrac{\dfrac{10}{3}}{1}=\dfrac{10}{3}A,\)
\(=>I5=\dfrac{U5}{R5}=\dfrac{10}{3}A\)
b, \(I1=0,1A=Im=I2345\)
\(=>Uab=I2345.R2345=0,1.\dfrac{6\left[8+\dfrac{6.12}{6+12}\right]}{6+8+\dfrac{6.12}{6+12}}=0,4V\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=2+2^2+2^3+2^4+...+2^{99}+2^{100}=2\left(1+2^2+2^3+2^4\right)+...+2^{96}\left(1+2^2+2^3+2^4\right)=2.31+2^6.31+...+2^{96}.31=31\left(2+2^6+...+2^{96}\right)⋮31\)
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VII:
1. older than
2. more expensive than
3. more difficult than
4. longer than
5. more modern than
6. younger than
7. more expensive
8. the coldest
9. larger
VI.
1. d → strongest
2. b → shorter
3. b → higher
4. d → as
5. d → youngest
6. d → than
VII.
1. older than
2. more expensive than
3. more difficult than
4. longer than
5. more modern
6. the youngest
7. more expensive
8. the coldest
9. larger than
VIII.
1. c
2. c
3. a
4. c
5. b
12: Gọi vận tốc lúc về là x
Theo đề, ta có: x/60=1:0,8=5/4
=>x=75
11:
b: k=xy=4,5
Khi y=-0,5 thì x=4,5/-0,5=-9
c: v2*t2=v1*t1
=>t2/t1=v1/v2=5/6
d: Chiều dài và chiều rộng là hai đại lượng tỉ lệ nghịch
=>Nếu tăng chiều dài lên a lần và muốn giữ nguyên diện tích thì cần giảm chiều rộng đi a lần