x+3/22=27/121.11/9 mình đang cần gấp cảm ơn ạ
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\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
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b: \(=\dfrac{3a-9-2a-6-6}{\left(a+3\right)\left(a-3\right)}=\dfrac{a-15}{a^2-9}\)
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3.(⅓x - ¼)² = ⅓
=> (\(\dfrac{1}{3x}\)- \(\dfrac{1}{4}\) )2 = \(\dfrac{1}{9}\)
=>\(\left[{}\begin{matrix}\dfrac{1}{3x}-\dfrac{1}{4}=\dfrac{-1}{3}\\\dfrac{1}{3x}-\dfrac{1}{4}=\dfrac{1}{3}\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}\dfrac{1}{3x}=\dfrac{-1}{12}\\\dfrac{1}{3x}=\dfrac{7}{12}\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=-4\\x=\dfrac{12}{21}=\dfrac{4}{7}\end{matrix}\right.\)
Vậy, tập nghiệm x thỏa mãn là S=\(\left\{-4;\dfrac{4}{7}\right\}\)
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Lời giải:
$22+23-25+27-29+31-33$
$=22+(23-25)+(27-29)+(31-33)$
$=22+(-2)+(-2)+(-2)=22+(-2).3=22-6=16$
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\(x+\dfrac{3}{22}=\dfrac{27}{121}\cdot\dfrac{11}{9}\)
\(x+\dfrac{3}{22}=\dfrac{3}{11}\)
\(x=\dfrac{3}{11}-\dfrac{3}{22}\)
\(x=\dfrac{3}{22}\)
#Đang Bận Thở
`x +3/22=27/121 .11/9`
`x+3/22=(27.11)/(121.9)`
`x +3/22=(9.3.11)/(11.11.9)`
`x+3/22=3/11`
`x = 3/11-3/22`
`x=6/22-3/22`
`x=3/22`