Viết chương trình tính bình phương số chẵn có trong mảng gồm n phần tử. n≤100. Và kết luận khi mảng không có số chẵn
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
uses crt;
var a:array[1..100]of integer;
i,n,t,dem:integer;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=0;
dem:=0;
for i:=1 to n do
if a[i] mod 2=0 then
begin
t:=t+a[i];
inc(dem);
end;
writeln('Tong cac so chan la: ',t);
writeln('So luong so chan la: ',dem);
readln;
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 1:
uses crt;
var a:array[1..100]of real;
i,n:integer;
t:real;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=0;
for i:=1 to n do
if a[i] mod 2=0 then t:=t+a[i];
writeln(t:4:2);
readln;
end.
Câu 2:
uses crt;
var a:array[1..100]of integer;
i,n:integer;
t:real;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=1;
for i:=1 to n do
t:=t*a[i];
writeln(t:4:2);
readln;
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
#include <bits/stdc++.h>
using namespace std;
long long x,n,i,t1,t2,t3;
int main()
{
cin>>n;
t1=0; t2=0; t3=0;
for (i=1; i<=n; i++)
{
cin>>x;
t1+=x;
if (x%2==0) t2+=x;
else t3+=x;
}
cout<<t1<<" "<<t2<<" "<<t3;
return 0;
}
![](https://rs.olm.vn/images/avt/0.png?1311)
Program HOC24;
var i,n: byte;
t: longint:
a: array[1..50] of integer;
begin
write('Nhap n: '); readln(n);
for i:=1 to n do begin write('A[',i,']='); readln(a[i]); end;
t:=0;
write('Cac phan tu chan co trong mang la: ');
for i:=1 to n do
if a[i] mod 2=0 then
begin
write(a[i],' ');
t:=t+a[i];
end;
writeln;
write('Tong cac phan tu chan do la: ',t);
readln
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
uses crt;
var x,i,n,dem:integer;
begin
clrscr;
readln(n);
dem:=0;
for i:=1 to n do
begin
readln(x);
if x mod 2=0 then inc(dem);
end;
writeln(dem);
readln;
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
Program HOC24;
var a: array[1..50] of integer;
i,n: byte;
t: longint;
begin
write('Nhap N: '); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
write('Cac phan tu chan trong mang la: ');
for i:=1 to n do
if a[i] mod 2=0 then
begin
write(a[i],' ');
t:=t+a[i];
end;
writeln;
write('Tong cac phan tu chan trong day la: ',t);
readln
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 1:
uses crt;
var a:array[1..200]of integer;
i,n,t:integer;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=0;
for i:=1 to n do
if a[i] mod 2=0 then t:=t+a[i];
writeln(t);
readln;
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
uses crt;
var a:array[1..100]of integer;
i,n,dem,max,t,min,dem1:integer;
begin
clrscr;
write('n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
dem:=0;
max:=-32000;
for i:=1 to n do
begin
if a[i] mod 2=0 then
begin
dem:=dem+1;
if max<a[i] then max:=a[i];
end;
if dem=0 then writeln('Trong day khong co so chan')
else begin
writeln('So so chan la: ',dem);
writeln('So chan lon nhat la: ',max);
end;
t:=0;
for i:=1 to n do
if i mod 2=1 then t:=t+a[i];
writeln('Tong cac so o vi tri le la: ',t);
min:=maxint;
dem1:=0;
for i:=1 to n do
if a[i] mod 2<>0 then
begin
inc(dem1);
if min>a[i] then min:=a[i];
end;
if dem1=0 then writeln('Trong day khong co so le')
else writeln('So le nho nhat la: ',min);
readln;
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
6:
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n,A[100],i,dem=0;
cin>>n;
for (int i=1; i<=n; i++) cin>>A[i];
for (int i=1;i<=n; i++)
if (A[i]%2!=0) dem++;
cout<<dem;
return 0;
}
5:
#include <bits/stdc++.h>
using namespace std;
int main()
{
long long n,nn=1e6,A[1000];
cin>>n;
for (int i=1; i<=n; i++) cin>>A[i];
for (int i=1; i<=n; i++)
nn=min(nn,A[i]);
for (int i=1; i<=n; i++)
if (nn==A[i]) cout<<i<<" ";
return 0;
}
uses crt;
var a:array[1..100]of integer;
i,n,t,dem:integer;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=0;
dem:=0;
for i:=1 to n do
if a[i] mod 2=0 then
begin
inc(dem);
t:=t+sqr(a[i]);
end;
if dem=0 then writeln('mang khong co so chan')
else writeln('Tong binh phuong cac so chan la: ',t);
readln;
end.