120+120=?????/ giúp mình với
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\(\left(2x+1\right)\left(y-1\right)=-7\\ \Rightarrow2x+1;y-1\in U_{\left(-7\right)}=\left\{-7;-1;1;7\right\}\)
\(TH1\) | \(TH2\) | \(TH3\) | \(TH4\) | |
\(2x+1\) | \(1\) | \(-1\) | \(7\) | \(-7\) |
\(y-1\) | \(-7\) | \(7\) | \(-1\) | \(1\) |
\(x\) | \(0\) | \(-1\) | \(3\) | \(-4\) |
\(y\) | \(-6\) | \(8\) | \(0\) | \(2\) |
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\(90-120\div x\times0,3=45\)
\(120\times\dfrac{1}{x}\times0,3=90-45\)
\(\dfrac{36}{x}=45\)
\(x=\dfrac{4}{5}\)
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90 - 120 : x . 0,3 = 45
120 : x . 0,3 = 90 - 45
120 : x . 0,3 = 45
120 : x = 45 : 0,3
120 : x = 150
x = 120 : 150
x = 0.8
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17.86.14.17-120
=17.(86+14)-120
=17.100-120
=1700-120
=1580
#Hok_tốt
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TL :
120 : 54 - [ 50 : 2 - 32 - 2 x 4 ]
120 : 54 - [ 50 : 2 - 9 - 8 ]
120 : 54 - [ 25 - 1 ]
120 : 54 - 24
120 : 30
4
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2x² - 14x - 120 = 0
<=>2.(x2-7x-60)=0
<=>x2-7x-60=0
<=>x2-12x+5x-60=0
<=>x.(x-12)+5.(x-12)=0
<=>(x-12)(x+5)=0
<=>x-12=0 hoặc x+5=0
<=>x=12 hoặc x=-5
= 240 nha
bằng 240