y + 5/7-2/5=38/35
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\(y+\frac{5}{7}-\frac{2}{5}=\frac{38}{35}\)
\(y+\frac{5}{7}=\frac{38}{35}+\frac{2}{5}\)
\(y+\frac{5}{7}=\frac{52}{35}\)
\(y=\frac{52}{35}-\frac{5}{7}\)
\(y=\frac{27}{35}\)
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35 . 34 + 35 . 38 + 65 . 75 + 65 . 45 + 35 . 34 =
= 35 . 34 + 35 . 38 + 35 . 34 + 65 . 75 + 65 . 45
= 35 . ( 34 + 38 + 34 ) + 65 . ( 75 + 45 )
= 35 . 110 + 65 . 110
= 110 . ( 35 + 65 )
= 110 . 100
= 11000
Hok tốt!!!!!!!!!!!!!
a) Tính bằng cách hợp lí nhất :
35 . 34 + 35 . 38 + 65 . 75 + 65 . 45 + 35 . 34
= 35 . 34 + 35 . 38 + 35 . 34 + 65 . 75 + 65 . 45
= 35 . ( 34 + 38 + 34 ) + 65 . ( 75 + 45 )
= 35 . 106 + 65 . 120
= 3710 + 7800
= 11510
3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 . 12
= 3 . 8 . 25 + 4 . 6 . 37 + 2 . 12 . 38
= 24 . 25 + 24 . 37 + 24 . 38
= 24 . ( 25 + 37 + 38 )
= 24 . 100
= 2400
b) Tìm số tự nhiên x, biết :
( x - 5 ) ( x + 7 ) = 0
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-7\end{cases}}}.\)
Vậy .......
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\frac{a}{b}+\frac{5}{7}\right).\frac{4}{5}=\frac{38}{35}\)
\(\left(\frac{a}{b}+\frac{5}{7}\right)=\frac{38}{35}:\frac{4}{5}\)
\(\left(\frac{a}{b}+\frac{5}{7}\right)=\frac{19}{14}\)
\(\frac{a}{b}=\frac{19}{14}-\frac{5}{7}\)
\(\frac{a}{b}=\frac{9}{14}\)
Vậy \(\frac{a}{b}=\frac{9}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
60) \(\sqrt{7-3\sqrt{5}}=\dfrac{\sqrt{14-6\sqrt{5}}}{\sqrt{2}}=\dfrac{\left(3-\sqrt{5}\right)}{\sqrt{2}}=\dfrac{3\sqrt{2}-\sqrt{10}}{2}\)
59) \(\sqrt{6+\sqrt{35}}=\dfrac{\sqrt{12+2\sqrt{35}}}{\sqrt{2}}=\dfrac{\sqrt{7}+\sqrt{5}}{\sqrt{2}}=\dfrac{\sqrt{14}+\sqrt{10}}{2}\)
61) \(\sqrt{23+3\sqrt{5}}=\dfrac{\sqrt{46+6\sqrt{5}}}{\sqrt{2}}=\dfrac{3\sqrt{5}+1}{\sqrt{2}}=\dfrac{3\sqrt{10}+\sqrt{2}}{2}\)
62) \(\sqrt{7-\sqrt{33}}=\dfrac{\sqrt{14-2\sqrt{33}}}{\sqrt{2}}=\dfrac{\sqrt{11}-\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{22}-\sqrt{6}}{2}\)
63) \(\sqrt{8+\sqrt{55}}=\dfrac{\sqrt{16+2\sqrt{55}}}{\sqrt{2}}=\dfrac{\sqrt{11}+\sqrt{5}}{\sqrt{2}}=\dfrac{\sqrt{22}+\sqrt{10}}{2}\)
Câu 64 và 38 bạn làm đc ko ạ? Vs cả bạn giải chi tiết hơn giùm mình đc ko ạ?
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35 . 34 + 35 . 38 +5 .28 .7
= 35 . 34 + 35 . 38 + 35 . 28
= 35 .( 34+38+28)
=35.100
=3500
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\(a,\) Số số hạng là \(\left(40-2\right):2+1=20\left(số\right)\)
Tổng là \(\left(40+2\right)\times20:2=420\)
\(b,\) Số số hạng là \(\left(39-1\right):2+1=20\left(số\right)\)
Tổng là \(\left(39+1\right)\times20:2=400\)
a) 2 + 4 + 6 + 8 + ... + 34 + 36 + 38 + 40
= ( 2 + 42 ) + ( 4 + 38 ) + .... + ( 20 + 22 )
= 42 \(\times\) 10
= 420
b) 1 + 3 + 5 + 7 + ... + 35 + 37 + 39
= ( 1 + 39 ) + ( 3 + 37 ) + ...+ ( 19 + 21 )
= 40 \(\times\) 10
= 400
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57.\(\sqrt{8-\sqrt{55}}=\sqrt{\dfrac{16-2.\sqrt{5}.\sqrt{11}}{2}}=\sqrt{\dfrac{\sqrt{11}^2-2.\sqrt{5}.\sqrt{11}+\left(\sqrt{5}\right)^2}{2}}\)
\(=\sqrt{\dfrac{\left(\sqrt{11}-\sqrt{5}\right)^2}{2}}=\dfrac{\left|\sqrt{11}-\sqrt{5}\right|}{\sqrt{2}}=\dfrac{\sqrt{11}-\sqrt{5}}{\sqrt{2}}\)
58. \(\sqrt{7+\sqrt{33}}=\sqrt{\dfrac{14+2\sqrt{3}.\sqrt{11}}{2}}=\sqrt{\dfrac{\left(\sqrt{11}\right)^2+2\sqrt{3}.\sqrt{11}+\left(\sqrt{3}\right)^2}{2}}\)
\(=\sqrt{\dfrac{\left(\sqrt{11}+\sqrt{3}\right)^2}{2}}=\dfrac{\left|\sqrt{11}+\sqrt{3}\right|}{\sqrt{2}}=\dfrac{\sqrt{11}+\sqrt{3}}{\sqrt{2}}\)
mấy câu dưới bạn cũng làm tương tự thôi
60) \(\sqrt{7-3\sqrt{5}}=\dfrac{\sqrt{14-6\sqrt{5}}}{\sqrt{2}}=\dfrac{3-\sqrt{5}}{\sqrt{2}}=\dfrac{3\sqrt{2}-\sqrt{10}}{2}\)
61) \(\sqrt{23+3\sqrt{5}}=\dfrac{\sqrt{46+6\sqrt{5}}}{\sqrt{2}}=\dfrac{3\sqrt{5}+1}{\sqrt{2}}=\dfrac{3\sqrt{10}+\sqrt{2}}{2}\)
62) \(\sqrt{7-\sqrt{33}}=\dfrac{\sqrt{14-2\sqrt{33}}}{\sqrt{2}}=\dfrac{\sqrt{11}-\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{22}-\sqrt{6}}{2}\)
63) \(\sqrt{8+\sqrt{55}}=\dfrac{\sqrt{16+2\sqrt{55}}}{\sqrt{2}}=\dfrac{\sqrt{11}+\sqrt{5}}{\sqrt{2}}=\dfrac{\sqrt{22}+\sqrt{10}}{2}\)