Câu 15. (1,0 điểm) Tính bằng cách hợp lí.
a) 21 . 169 + ($-$69) . 21;
b) 21 . ($-$25) . ($-$3) . ($-$4).
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Lời giải:
a. $=-(37+63)+[25+(-25)]+(-9)=-100+0+(-9)=-(100+9)=-109$
b. $=[1+(-3)]+[5+(-7)]+....+[21+(-23)]$
$=\underbrace{(-2)+(-2)+....+(-2)}_{6}=(-2).6=-12$
c. $=-(280+20)+[-(79+21)]=-300+(-100)=-(300+100)=-400$
d. $=[-(27+43)]+[-(208+102)]=-70+(-310)=-(70+310)=-380$
e. $=(38+120)-(12+46)=158-58=100$
f. $=9+15+11+24=(9+11)+(15+24)=20+39=59$
\(21+21+21+...+21+21+16+16+16+...+16.\) (84 số 21 và 21 số 16)
\(=84\cdot21+21\cdot16=21\left(84+16\right)=21\cdot100=2100\)
\(A=\frac{9}{15.18}+\frac{9}{18.21}+.....+\frac{9}{89.92}\)
\(A=3.\left(\frac{3}{15.18}+\frac{3}{18.21}+....+\frac{3}{89.92}\right)\)
\(A=3.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+......+\frac{1}{89}-\frac{1}{92}\right)\)
\(A=3.\left(\frac{1}{15}-\frac{1}{92}\right)\)
\(A=3.\frac{77}{1380}=\frac{77}{460}\)
a,\(\frac{1}{5}\times\frac{2}{9}\div\frac{1}{15}\)
\(=\frac{1}{5}\times\frac{2}{9}\times15\)
\(=\left(\frac{1}{5}\times15\right)\times\frac{2}{9}\)
\(=3\times\frac{2}{9}\)
\(=\frac{2}{3}\)
b\(\frac{4}{15}\times\frac{7}{15}\times\frac{5}{4}\)
\(=\left(\frac{4}{15}\times\frac{5}{4}\right)\times\frac{7}{15}\)
\(=\frac{1}{3}\times\frac{7}{15}\)
\(=\frac{7}{45}\)
c,\(\frac{21}{23}\times\frac{5}{11}\times\frac{44}{?}\)
d,\(26\times\frac{13}{42}\div13\)
\(=\left(26\div13\right)\times\frac{13}{42}\)
\(=2\times\frac{13}{42}\)
\(=\frac{13}{21}\)
\(\dfrac{45.21.25}{7.15.36}=\dfrac{3.3.3.5.7.5.5}{7.5.3.3.2.3.2}=\dfrac{25}{4}\)
45\7 x 21\15 x 25/36
=45x21x25/7x15x36
=15x3x7x3x25/7x15x3x12
=3x25/12
=75/12
=25/4
a, \(\frac{4}{20}+\frac{16}{42}+\frac{6}{15}+\frac{-3}{5}+\frac{-10}{21}+\frac{3}{20}\)
\(=\left(\frac{4}{20}+\frac{-3}{5}+\frac{6}{15}+\frac{3}{20}\right)\)\(+\left(\frac{16}{42}+\frac{2}{21}+\frac{-10}{21}\right)\)
\(=\left(\frac{4}{20}+\frac{-12}{20}+\frac{8}{20}+\frac{3}{20}\right)\)\(+\left(\frac{8}{21}+\frac{2}{21}+\frac{-10}{21}\right)\)
\(=\frac{3}{20}\)
b,\(\frac{42}{46}+\frac{250}{186}+\frac{-2121}{2323}+\frac{-125125}{143143}\)
\(=\frac{21}{23}+\frac{125}{93}+\frac{-21}{23}+\frac{-125}{143}\)
\(=\left(\frac{21}{23}+\frac{-21}{23}\right)+\left(\frac{125}{93}+\frac{-125}{143}\right)\)
\(=\frac{6250}{13299}\)
\(\Rightarrow A=\left(\frac{27}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+\frac{1}{2}\)
\(\Rightarrow A=1+1+\frac{1}{2}\)
\(\Rightarrow A=\frac{5}{2}\)
tíc mình nha
a)15/34-8/21+19/34-34/21
=(15/34+19/34)+(-8/21-34/21)
= 34/34+(-42/21)
=1+(-2)
=-1
đề tự ghi lại nha
=\(\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{-8}{21}-\frac{34}{21}\right)\)
=\(\frac{34}{34}+\frac{-42}{21}\)
=\(1+\left(-2\right)\)
=\(-1\)
a) 21 . 169 + (−69) . 21;
= 21 . [169 + (-69)
= 21 . 100 = 2100
b) 21 . (−25) . (−3) . (−4).
= [21 . (-3)] . [(-25) . (-4)]
= (-63) . 100 = -6300
a) 21 . 169 + (−−69) . 21
= 21 . [169 + (−−69)]
= 21 . 100 = 2 100.
b) 21 . (−−25) . (−−3) . (−−4)
= [21 . (−−3)] . [(−−25) . (−−4)]
= (−−63) . 100 = −−6 300.