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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(12,25+\left(-21,37\right)-\left(14,67-21,75\right)\)
\(=12,25-21,37-14,67+21,75\)
\(=12,25+21,75-21,37-14,63-0,04\)
\(=34-36-0,04\)
= -2-0,04=-2,04
![](https://rs.olm.vn/images/avt/0.png?1311)
120:{54-[50:2.(3^2-2.4)]}
= 120:{ 54-[25.(9-8)]}
= 120:{54-[25.1]}
= 120:{54-25}
= 120:29
=\(\dfrac{120}{29}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{323}\\ =\dfrac{1}{2}\times\left(\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+...+\dfrac{2}{17\times19}\right)\\=\dfrac{1}{2}\times\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{17}-\dfrac{1}{19}\right)\\ =\dfrac{1}{2}\times\left(\dfrac{1}{1}-\dfrac{1}{19}\right)\\ =\dfrac{1}{2}\times\dfrac{18}{19}=\dfrac{9}{19}\)
đề bài đây:
\(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{323}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= (8x125)x(50x2)x(45x10+45)
= 1000x100x495
= 49.500.000
![](https://rs.olm.vn/images/avt/0.png?1311)
g: \(\left(-3\right)^4\cdot10=81\cdot10=810\)
i: \(\left(-2\right)\cdot\left(-2\right)\cdot\left(-4\right)\cdot\left(-4\right)\cdot\left(-4\right)\)
\(=-2\cdot2\cdot4\cdot4\cdot4\)
\(=-2^2\cdot2^2\cdot2^2\cdot2^2=-2^8=-256\)
l: \(26\cdot\left(-125\right)-125\cdot\left(-36\right)\)
\(=125\cdot\left(-26\right)+125\cdot36\)
\(=125\left(-26+36\right)\)
\(=125\cdot10=1250\)
n: \(\left(-37\right)\cdot84+37\cdot\left(-16\right)\)
\(=37\cdot\left(-84\right)+37\cdot\left(-16\right)\)
\(=37\left(-84-16\right)=37\cdot\left(-100\right)=-3700\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề: \(45\cdot67+45\cdot34-45\)
\(=45\cdot\left(67+34-1\right)\)
\(=45\cdot100\)
\(=4500\)
e: \(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^8}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}=\dfrac{5}{2}\)
g: \(=125+\dfrac{3}{5}-97-\dfrac{2}{3}+97+\dfrac{2}{5}-125-\dfrac{1}{3}=0\)