X + 20 = 110
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![](https://rs.olm.vn/images/avt/0.png?1311)
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\(240-\left(x+5\right)=137\)
\(x+5=240-137\)
\(x+5=103\)
\(x=103-5=98\)
b) \(\left(2x-10\right)-20=110\)
\(2x-10=110+20\)
\(2x-10=130\)
\(2x=130+10\)
\(2x=140\)
\(x=140:2=70\)
\(a,240-\left(x+5\right)=137\\ x+5=103\\ x=98\\ b,\left(2x-10\right)-20=110\\ 2x-10=130\\ 2x=140\\ x=70\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left|x+\frac{1}{2}\right|+\left|x+\frac{1}{6}\right|+\left|x+\frac{1}{12}\right|+...\left|x+\frac{1}{110}\right|=11x\)
\(\Leftrightarrow\left|x+\frac{1}{2}\right|+\left|x+\frac{1}{6}\right|+\left|x+\frac{1}{12}\right|+...\left|x+\frac{1}{110}\right|\ge0\)
\(\rightarrow11x\ge0\rightarrow x\ge0\)
\(\text{Ta có:}\)
\(x+\frac{1}{2}+...+x+\frac{1}{110}=11x\)
\(\rightarrow10x+\frac{10}{11}=11x\)
\(\rightarrow x=\frac{10}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề
\(\dfrac{2}{1^2}\cdot\dfrac{6}{2^2}\cdot\dfrac{12}{3^3}\cdot.......\cdot\dfrac{110}{10^2}\cdot x=-20\)
\(\dfrac{2}{1\cdot1}\cdot\dfrac{2\cdot3}{2\cdot2}\cdot\cdot\cdot\cdot\dfrac{11\cdot10}{10\cdot10}\cdot x=-20\)
\(\dfrac{\left(2\cdot3\cdot4\cdot....\cdot11\right)}{\left(1\cdot2\cdot3\cdot4\cdot...\cdot10\right)}\cdot\dfrac{\left(1\cdot2\cdot3\cdot4\cdot5\cdot...\cdot10\right)}{\left(1\cdot2\cdot3\cdot4\cdot...\cdot10\right)}\cdot x=-20\)
\(11\cdot x=-20\\ x=-\dfrac{20}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\)
\(=\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{11-10}{10.11}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\)
\(=1-\frac{1}{11}=\frac{10}{11}\)
Phương trình ban đầu tương đương với:
\(10x+\frac{10}{11}=11x\)
\(\Leftrightarrow x=\frac{10}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow-2x+\dfrac{3}{20}=1-\dfrac{1}{2}+1-\dfrac{1}{6}+...+1-\dfrac{1}{110}\)
\(\Leftrightarrow-2x+\dfrac{3}{20}=10-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{10}-\dfrac{1}{11}\right)\)
\(\Leftrightarrow-2x+\dfrac{3}{20}=10-\dfrac{10}{11}=\dfrac{100}{11}\)
=>-2x=1967/220
hay x=-1967/440
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 120 - 20 : x = 110
20:x= 120 - 110
20:x= 10
x= 20:10=2
b) 213 - ( x - 13 ) = 1442 : 14
213 - (x-13)=103
x-13= 213 - 103
x-13=110
x=110+13
x=123
c) 2550 : [ 120 - ( x - 5 ) ] = 25
120 - (x-5) = 2550:25
120 - (x-5)=102
x-5 = 120 - 102
x-5= 18
x=18+5
x=23
x+20=110
x=110-20
x=90![Kết quả hình ảnh cho anh photokatsu](http://orig09.deviantart.net/54f0/f/2016/283/6/a/_render__29__by_nyokarrs-daki442.png)
= 90 k nha mình mới vào.