x + 23 = 40
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![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 23. [(12.X+39):3] = 4623
⇒(12.X+39):3 = 201
⇒12.X+39 = 603
⇒12.X = 564
⇒X = 47
![](https://rs.olm.vn/images/avt/0.png?1311)
`@` `\text {Ans}`
`\downarrow`
`2000 - 40 \times 27 - 40 \times 23`
`= 2000 - 40 \times (27 + 23)`
`= 2000 - 40 \times 50`
`= 40 \times 50 - 40 \times 50`
`=0`
\(2000-40x27-40x23\)
\(=40x50-\left(40x27+40x23\right)\)
\(=40x50-\left[40x\left(27+23\right)\right]\)
\(=40x50-40x50=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
23 * [ ( 12 * x + 39 ) : 3 ] = 23 + 40 * 115
23 x [ ( 12 x x + 39 ) : 3 ] = 4623
( 12 x x + 39 ) : 3 = 4623 : 23
( 12 x x + 39 ) : 3 = 201
12 x x + 39 = 201 x 3
12 x x + 39 = 603
12 x x = 603 - 39
12 x x = 564
x = 564 : 12
x = 47
k mik nha các bn
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![](https://rs.olm.vn/images/avt/0.png?1311)
`(23+x)/(40+x)=3/4(x ne -40)`
`=>4(23+x)=3(40+x)`
`=>92+4x=120+3x`
`=>4x-3x=120-92`
`=>x=28`
Vậy `x=28`
\(\dfrac{23+x}{40+x}=\dfrac{3}{4}\)
\(\Rightarrow4.\left(23+x\right)=3.\left(40+x\right)\)
\(92+4x=120+3x\)
\(4x-3x=120-92\)
\(1x=28\)
\(x=28:1\)
\(x=28\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lê Hoàng Khả Nhi
a, x.0 = 0
=> x = 0
b, 23( x -4) = 23
=> x -4 = 23/23
=> x -4 = 1
=> x = 1 + 4
=> x = 5
c, 12x + 40 = 76
=> 12x = 76 -40
=> 12x = 36
=> x = 36/12
=> x = 3
a) \(x.0=0\)
\(=>x\)có vô số nghiệm
b) \(23\left(x-4\right)=23\)
\(23x-92=23\)
\(23x=115\)
\(x=5\)
vậy \(x=5\)
c) \(12x+40=76\)
\(12x=36\)
\(x=3\)
vậy \(x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
23+x/40+x=3/4
=>x/40+x=3/4-23=-89/4
=>x/40+40x/40=-89/4
=>(x+40x)/40=-89/4
=>50x/40=-89/4
=>50x=-89/4.40=-890
=>x=-17,8
k cho mk nha pn!!!!!
x = 17
mk tk bạn rồi đấy
\(x+23=40\)
\(x=40-23\)
\(x=17\)
k mk nha
thank you