Tính theo cách thuận tiện nhất:
\(\frac{5}{13}\)x \(\frac{4}{11}\)+ \(\frac{8}{13}\)x \(\frac{4}{11}\)
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\(\frac{\frac{3}{11}-\frac{3}{13}+\frac{3}{17}-\frac{3}{19}}{\frac{4}{11}-\frac{4}{13}+\frac{4}{17}-\frac{4}{19}}=\frac{3\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}-\frac{1}{19}\right)}{4\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}-\frac{1}{19}\right)}=\frac{3}{4}\)
\(\frac{3.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}-\frac{1}{19}\right)}{4.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}-\frac{1}{19}\right)}\) = \(\frac{3}{4}\)
--------------------- Hok Tốt-----------------------------
13/19 x 23/11 - 13/19 x 8/11 - 13/19 x 4/11
= 13/19 x (23/11 - 8/11 - 4/11)
= 13/19 x 1
= 13/19
\(\dfrac{13}{19}\times\dfrac{23}{11}-\dfrac{13}{19}\times\dfrac{8}{11}-\dfrac{13}{19}\times\dfrac{4}{11}\\ =\dfrac{13}{19}\times\left(\dfrac{23}{11}-\dfrac{8}{11}-\dfrac{4}{11}\right)\\ =\dfrac{13}{19}\times1=\dfrac{13}{19}\)
a, \(\frac{6}{7}.\frac{16}{15}.\frac{7}{6}.\frac{21}{32}=\frac{6}{7}.\frac{7}{6}.\frac{16}{15}.\frac{21}{32}\)=\(1.\frac{16}{15}.\frac{21}{32}=\frac{7}{5.2}=\frac{7}{10}\)
Phần b T2
c,\(\frac{7}{4}.\frac{11}{21}+\frac{11}{21}.\frac{5}{4}=\frac{11}{21}.\left(\frac{7}{4}+\frac{5}{4}\right)\)=\(\frac{11}{21}.3=\frac{11}{7}\)
a) (21x11x2x17x4)/(11x17x21x3)
=(21x11x2x17x4)/(11x17x21x3)
=8/3
b) (5x7x13x2)/(7x2x13x5x5)
=1/5
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a \(\frac{4}{18}+\frac{5}{13}+\frac{7}{9}+\frac{21}{13}\)
= \(\left(\frac{4}{18}+\frac{7}{9}\right)+\left(\frac{5}{13}+\frac{21}{13}\right)\)
= \(1+2\)
= \(3\)
b \(\frac{4}{3}-\frac{2}{7}-\frac{5}{7}+\frac{2}{3}\)
= \(\left(\frac{4}{3}-\frac{2}{3}\right)-\left(\frac{2}{7}+\frac{5}{7}\right)\)
= \(\frac{2}{3}-1\)
= \(-\frac{1}{3}\)
\(=\frac{4}{11}\times\left(\frac{5}{13}+\frac{8}{13}\right)\)
\(=\frac{4}{11}\times1\)
\(=\frac{4}{11}\)
Chúc cậu học tốt
\(=\frac{4}{11}\times\left(\frac{5}{13}+\frac{8}{13}\right)\)
\(=\frac{4}{11}\times1\)
\(=\frac{4}{11}\)