câu 2.Tính bằng cách thuận tiện nhất( mẫu 3)
7/8x9/5x8/3x5
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
= 5 x 7 + 5 x 4 + 5 x 8 + 5 x 1
= 5 x ( 7 + 4 + 8 + 1 )
= 5 x 20
= 100
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{5}x\frac{8}{27}x\frac{5}{3}=\frac{3}{3}x\frac{5}{5}x\frac{8}{27}=\frac{8}{27}\)
\(\frac{7}{19}x\frac{1}{3}+\frac{7}{19}x\frac{2}{3}=\frac{7}{19}x\left(\frac{1}{3}+\frac{2}{3}\right)=\frac{7}{19}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9\cdot8\cdot33}{56\cdot54\cdot11}=\frac{9\cdot8\cdot3\cdot11}{8\cdot7\cdot9\cdot3\cdot2\cdot11}=\frac{1}{7\cdot2}=\frac{1}{14}\)
\(\frac{8\cdot15+16\cdot4-8\cdot21}{16\cdot5-8\cdot9}=\frac{8\cdot15+8\cdot2\cdot4-8\cdot21}{2\cdot8\cdot5-8\cdot9}=\frac{8\cdot15+8\cdot8-8\cdot21}{8\cdot10-8\cdot9}=\frac{8\left(15+8-21\right)}{8\left(10-9\right)}=\frac{8\cdot2}{8\cdot1}=\frac{2}{1}=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b ) Đặt \(A=\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{101.103}\)
\(\Rightarrow A=\frac{5}{2}\left(\frac{5}{1}-\frac{5}{3}+\frac{5}{3}-\frac{5}{5}+....+\frac{5}{101}-\frac{5}{103}\right)\)
\(\Rightarrow A=\frac{5}{2}\left(5-\frac{5}{103}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`x : 5/2 = 7/3`
`=> x= 7/3 xx 5/2`
`=>x= 35/6`
__
`23,7 xx 49 +23,7 xx 51`
`= 23,7 xx (49+51)`
`= 23,7 xx 100`
`=2370`
Lời giải:
a.
$x=\frac{7}{3}\times \frac{5}{2}=\frac{35}{6}$
b.
$23,7\times 49+23,7\times 51=23,7\times (49+51)=23,7\times 100=2370$
=7/8.8/3.9/5.5
=7/3.9
=21
`7/8xx9/5xx8/3xx5=[7xx3xx3xx8xx5]/[8xx5xx3]=7xx3=21`