10101x(5/10101-5/20202+5/30303-5/40404). mọi người giúp em với.
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\(10101.\left(\frac{5}{10101}-\frac{5}{20202}-\frac{5}{30303}-\frac{5}{40404}\right)=\frac{10101.5}{10101}-\frac{10101.5}{10101.2}-\frac{10101.5}{10101.3}-\frac{10101.5}{10101.4}\)\(=5-\frac{5}{2}-\frac{5}{3}-\frac{5}{4}=-\frac{5}{12}\)(nhưng lớp 4 chưa học phân số âm)
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=10101x5/10101-10101x5/20202+10101x5/30303-10101x5/40404
=5-5/2+5/3-5/4
=35/12
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10101x(5/10101-5/20202+5/30303-5/40404)=10101x5/10101-10101x5/10101x2+10101x5/10101x3-10101x5/10101x4
=5-5/2+5/3-5/4
=35/12
k mk nha
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\(10101.\left(\frac{5}{10101}-\frac{5}{20202}+\frac{5}{30303}+\frac{5}{40404}\right)\)
\(=10101.\frac{5}{10101}-10101.\frac{5}{20202}+10101.\frac{5}{30303}+10101.\frac{5}{40404}\)
\(=5-\frac{5}{2}+\frac{5}{3}+\frac{5}{4}\)
\(=\frac{60}{12}-\frac{30}{12}+\frac{20}{12}+\frac{15}{12}\)
\(=\frac{60-30+20+15}{12}\)
\(=\frac{65}{12}\)
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\(10101\times\left(\frac{5}{10101}-\frac{5}{20202}+\frac{5}{30303}+\frac{5}{40404}\right)\)
\(=10101\times\left(\frac{10}{20202}-\frac{5}{20202}+\frac{20}{121212}+\frac{15}{121212}\right)\)
\(=10101\times\left(\frac{5}{20202}+\frac{25}{121212}\right)\)
\(=10101\times\frac{55}{121212}\)
\(=\frac{65}{12}\)
10101 x ( 5/10101 - 5/20202 + 5/30303 - 5/40404 ) = 10101 x ( 5/10101 - 5/10101x2 + 5/10101x3 - 5/10101 x 4 )
= 10101 x ( 5/10101 x - 5/10101 x 1/2 + 5/10101 x 1/3 - 5/10101 x 1/4 )
= 10101 x 5/10101 x ( 1 - 1/2 + 1/3 - 1/4 )
= 10101 x 5/10101 x 1 - 7/12
= 10101 x 5/10101 x 3/4
= 10101 x 15/40404
= 151515/40404
= 15/4