Tìm x biết 9378 - x : 120 = 7295
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\(\dfrac{1}{120}\cdot120+x:\dfrac{1}{3}=-4\)
\(\Leftrightarrow1+x\cdot3=-4\)
\(\Leftrightarrow3x=-5\)
\(\Leftrightarrow x=-\dfrac{5}{3}\)
\(\dfrac{1}{120}.120+x:\dfrac{1}{3}=-4\)
\(1+x:\dfrac{1}{3}=-4\)
\(x:\dfrac{1}{3}=-4-1\)
\(x:\dfrac{1}{3}=-5\)
\(x=-5.\dfrac{1}{3}\)
\(x=\dfrac{-5}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 120 - 20 : x = 110
20:x= 120 - 110
20:x= 10
x= 20:10=2
b) 213 - ( x - 13 ) = 1442 : 14
213 - (x-13)=103
x-13= 213 - 103
x-13=110
x=110+13
x=123
c) 2550 : [ 120 - ( x - 5 ) ] = 25
120 - (x-5) = 2550:25
120 - (x-5)=102
x-5 = 120 - 102
x-5= 18
x=18+5
x=23
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x - 120: 30 = 40
x -40 =40
x =40+40
x =80
b) (x + 120) : 20 = 8
(x+ 120) = 8x20
x+120 =160
x = 160-120
x = 40
c) (x + 5). 3 = 300
x+5=300:3
x+5=100
x=100-5
x=95
d) x.2 + 21 : 3= 27
x.2 +7=27
x.2 = 27-7
x.2= 20
x=20:2
x=10
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Đáp án cần chọn là: A
+) Vì 120⋮x nên x∈Ư(120)= {1;2;3;4;5;6;8;10;12;15;20;24;30;40;60;120}
+) Vì 200⋮x nênx∈Ư(200)={1;2;4;5;8;10;20;25;40;50;100;200}
Nên x∈ƯC(120;200)={1;2;4;5;8;10;20;40}mà x<40 nên x∈{1;2;4;5;8;10;20}.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x + 20%x =120
x*1 +20%x =120
x*(1+20%) =120
x*1,2 =120
x =120/1,2
x = 100
\(x+20\%x=120\)
\(\Rightarrow x+\frac{1}{5}x=120\)
\(\Rightarrow x.\left(1+\frac{1}{5}\right)=120\)
\(\Rightarrow x.\frac{6}{5}=120\)
\(\Rightarrow x=120:\frac{6}{5}\)
\(\Rightarrow x=100\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x + x * 2,7 +x*6,3=120
x *1 +x *2,7 + x * 6,3 =120
x * (1+ 2 ,7 + 6,3)=120
x * 10 =120
x =120:10
x=12
Vậy x=12
Nhé k cho mình và kết bạn nha !
9378 - x : 120 = 7295
x : 120 = 9378 - 7295
x : 120 = 2083
x = 2083 x 120
x = 249960