Tính hợp lí : 2022.2022 - 2025.2019
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
H9
HT.Phong (9A5)
CTVHS
17 tháng 7 2023
a) Ta có:
\(A=2021\cdot2023\)
\(A=\left(2022-1\right)\cdot\left(2022+1\right)\)
\(A=2022^2+2022-2022-1\)
\(A=2022^2-1\)
Ta thấy: \(2022^2-1< 2022^2\)
Vậy: \(A< B\)
b) Ta có:
\(A=2^{30}=\left(2^3\right)^{10}=8^{10}\)
\(B=3^{20}=\left(3^2\right)^{10}=9^{10}\)
Ta thấy: \(8^{10}< 9^{10}\)
Vậy: \(A< B\)
22 tháng 7 2021
a)\(B=2022.2022\)
\(=\left(2021+1\right)2022\)
\(=2021.2022+2022\)
Vì \(2020< 2022\Rightarrow2021.2020< 2021.2022\Rightarrow2021.2020< 2021.2022+2022\)
hay \(A< B\)
22 tháng 7 2021
b)\(M=360.345-200\)
\(=360\left(344+1\right)-200\)
\(=360.344+360-200\)
\(=360.344+160< 340.344+161=N\)
\(\Rightarrow M< N\)
24 tháng 9 2021
a>b nhé anh vì 2022.2022 nó đã lớn hơn 2021.2023 rồi ạ
k cho em nếu đúng nhé
chúc anh học tốt
24 tháng 9 2021
Ta có:
A=2022x2022
=2022x(2023-1)
=2022 x 2023 - 2022 x 1
=2022x2024-2021
Lại có:
B = 2021 . 2023
B = ( 2022 - 1 ) . 2023
B = 2023 . 2022 - 2023 . 1
B = 2023 . 2022 - 2023
Ta thấy: 2022x2024-2021 > 2023x2022-2023
Suy ra A > B.
DN
30 tháng 12 2021
\(\left(-2021\right).\left(23+76\right)-2021=\left(-2021\right).99-2021=-202100\)
tính hợp lí
7 tháng 3 2022
\(5,-\dfrac{2}{7}-\left(\dfrac{5}{11}-\dfrac{9}{7}\right)+\dfrac{5}{11}=-\dfrac{2}{7}-\dfrac{5}{11}+\dfrac{9}{7}+\dfrac{5}{11}=\left(-\dfrac{2}{7}+\dfrac{9}{7}\right)-\left(\dfrac{5}{11}-\dfrac{5}{11}\right)=1-0=1\\ 6,\dfrac{2}{3}+\dfrac{-2}{5}+\dfrac{-5}{6}-\dfrac{13}{10}=\left(\dfrac{4}{6}+\dfrac{-5}{6}\right)+\left(\dfrac{-4}{10}-\dfrac{13}{10}\right)=\dfrac{-1}{6}+\dfrac{-17}{10}=\dfrac{-5}{30}+\dfrac{-51}{30}=\dfrac{-56}{30}=\dfrac{-28}{15}\)
\(7,\dfrac{-5}{9}+\dfrac{8}{15}+\dfrac{4}{-9}+\dfrac{7}{15}=\left(\dfrac{-5}{9}+\dfrac{-4}{9}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)=\left(-1\right)+1=0\\ 8,\left(\dfrac{12}{13}+7\right)-\left(-\dfrac{1}{13}+8\right)=\dfrac{12}{13}+7+\dfrac{1}{13}-8=\left(\dfrac{12}{13}+\dfrac{1}{13}\right)+\left(7-8\right)=1+\left(-1\right)=0\)
VN
Võ Ngọc Phương
CTVHS
VIP
24 tháng 8 2023
a) \(\left(\dfrac{3}{8}-\dfrac{1}{5}-\dfrac{1}{3}\right)+\left(\dfrac{5}{8}-1\dfrac{3}{7}-\dfrac{4}{7}\right)+\dfrac{1}{3}\)
\(=\dfrac{3}{8}-\dfrac{1}{5}-\dfrac{1}{3}+\dfrac{5}{8}-\dfrac{10}{7}-\dfrac{4}{7}+\dfrac{1}{3}\)
\(=\left(\dfrac{3}{8}+\dfrac{5}{8}\right)+\left(\dfrac{-1}{3}+\dfrac{1}{3}\right)+\left(\dfrac{-10}{7}-\dfrac{4}{7}\right)-\dfrac{1}{5}\)
\(=1+0+\left(-2\right)-\dfrac{1}{5}\)
\(=-1-\dfrac{1}{5}\)
\(=\dfrac{-6}{5}\)
b) \(-24.\left(\dfrac{1}{3}-\dfrac{1}{4}\right)^2-1,5\)
\(=-24.\left(\dfrac{1}{12}\right)^2-\dfrac{3}{2}\)
\(=-24.\dfrac{1}{144}-\dfrac{3}{2}\)
\(=\dfrac{-1}{6}-\dfrac{3}{2}=\dfrac{-1}{6}-\dfrac{9}{6}=\dfrac{-10}{6}=\dfrac{-5}{3}\)
c) \(2^2-\left(-\dfrac{5}{7}\right)^0+\left(\dfrac{1}{3}\right)^4.3^6\)
\(=4-1+\dfrac{1}{81}.729\)
\(=4-1+9\)
\(=3+9=12\)
d) \(23\dfrac{1}{3}:\left(\dfrac{-5}{7}\right)+13\dfrac{1}{3}:\dfrac{5}{7}\)
\(=\dfrac{-70}{3}.\dfrac{7}{5}+\dfrac{40}{3}.\dfrac{7}{5}\)
\(=\dfrac{7}{5}\left(\dfrac{-70}{3}-\dfrac{40}{3}\right)\)
\(=\dfrac{7}{5}.\left(-10\right)\)
\(=-14\)
e) \(\dfrac{3}{4}.\dfrac{8}{5}+\dfrac{6}{15}:\dfrac{4}{3}-1\dfrac{2}{5}:1\dfrac{1}{3}\)
\(=\dfrac{3}{4}.\dfrac{8}{5}+\dfrac{6}{15}.\dfrac{3}{4}-\dfrac{7}{5}.\dfrac{3}{4}\)
\(=\dfrac{3}{4}\left(\dfrac{8}{5}+\dfrac{6}{15}-\dfrac{7}{5}\right)\)
\(=\dfrac{3}{4}\left(\dfrac{24}{15}+\dfrac{6}{15}-\dfrac{21}{15}\right)\)
\(=\dfrac{3}{4}.\dfrac{9}{15}\)
\(=\dfrac{9}{20}\)
KV
1 tháng 11 2023
25.8.4.28.125
= 28.(25.4).(8.125)
= 28.100.1000
= 2800.1000
= 2800000
2025-2022 =3 ×2019 = 6057