3 1/3y + 16 3/4 =-13,25
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10/3 y + 67/4= -1325/100
10/3y= -1325/100 - 1675/100
10/3y = -3000/100
10/3y = 30
y= 30 : 10/3
y=9
10/3y+67/4=-1325/100
10/3y=-1235/100-67/4
10/3y=-30
y=-30:10/3
y=-9
Vậyy=-9
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Rightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)
\(\Rightarrow\dfrac{10}{3}x=\dfrac{-120}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{10}{3}\)
\(\Rightarrow x=-9\)
Vậy: ...
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)
\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)
\(x=-30.\dfrac{3}{10}\)
\(x=\dfrac{-90}{10}=-9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1\frac{1}{3}\cdot x+16\frac{3}{4}=13,25\)
\(\frac{4}{3}\cdot x=13,25-16\frac{3}{4}\)
\(\frac{4}{3}\cdot x=-3,5\)
\(x=-3,5:\frac{4}{3}\)
\(x=-2,625\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(=>\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)
\(\frac{10}{3}x=-30\)
x = -30 : \(\frac{10}{3}\)
= > x = -9
Đề bài thế này đúng ko: 3. 1/3y + 16. 3/4 = -13,25
3 . 1/3 y + 16.3/4=-13,25
y + 12 = -13,25
y = -13,25 -12
y= -25,25