Tìm x
156-(x+61)=82
5(x+35) = 515
x:5=x:6
(x-42)(x-21)=0
124+(118-x)=2
giúp mình nhé. Cảm ơn rất nhiều
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(x - 35) - 120 = 0
<=> x-35-120=0
<=> x=155
124 + (118 - x) = 217
<=> 242-x=217
<=> x=25
156 - (x + 61) = 82
<=> 156-x-61=82
<=> 95-x=82
<=> x=13
a)(x-35)-120=0 b)124+(118-x)=217 c)156-(x+61)=82
x-35 = 0+120=120 118-x =217-124=93 x+61 = 156-82=74
x = 120+35=155 x = 118-93=25 x =74-61=13
suy ra x=155 suy ra x= 25 suy ra x=13
a) ( x - 35 ) - 120 = 0
<=> x - 35 = 120
<=> x = 155
b) 124 + ( 118 - x ) = 217
<=> 118 - x = 93
<=> x = 25
c) 156 - ( x + 61 ) = 82
<=> x + 61 = 74
<=> x = 13
(x-35)-120=0
x-35 = 0 + 120
x-35 = 120
x = 120 + 35
x = 155
124+(118-x)=217
118-x = 217-124
118-x = 93
x = 118 - 93
x = 25
156-(x+61)=82
x + 61=156-82
x+61 = 74
x = 74 - 61
x = 13
(x-35)-120=0
x-35 = 0+120
x-35 = 120
x = 120-35
x = 85
124 + (118-x)=217
118-x=217-124
118-x=93
x=118-93
x=25
156-(x+61)=82
x+161=156-82
x+161=74
x=161-74
x=87
do la bai cua minh,co cho sai nao thi sua cho minh nhe
Tìm số tự nhiên x,biết:
a) ( x - 35 ) - 120 = 0
<=> x - 35 = 0 + 120
<=> x - 35 = 120
<=> x = 120 + 35
<=> x = 155
Vậy x = 155
b) 124 + ( 118 - x ) = 217
<=> 118 - x = 217 - 124
<=> 118 - x = 93
<=> x = 118 - 93
<=> x = 25
Vậy x = 25
c) 156 - ( x + 61 ) = 82
<=> x + 61 = 156 - 82
<=> x + 61 = 74
<=> x = 74 - 61
<=> x = 13
Vậy x = 13
a. (x - 35) - 120 = 0
x - 35 = 0 + 120
x = 120 + 35
x = 155
b. 124 + (118 - x) = 217
118 - x = 217 - 124
x = 118 - 93
x = 25
c. 156 - (x + 61) = 82
x + 61 = 156 - 82
x = 74 - 61
x = 13
a)
( x - 35 ) - 112 = 0
=> x - 35 = 0 + 112 = 112
=> x = 112 + 35 = 147
b)
124 + ( 118 - x ) = 27
=> 124 + 118 - x = 27
=> 242 - x = 27
=> x = 242 - 27 = 215
c)
156 - ( x + 61 ) = 82
=> 156 - x - 61 = 82
=> 95 - x = 82
=> x = 95 - 82 = 13
a)(x-35)-120=0
x-35 =0+120
x-35 =120
x =120+35
x =155
b)124+(118-x)=217
118-x =217-124
118-x =93
x=118-93
x=25
c)156-(x+61)=82
x+61=156-82
x+61 =74
x =74-61
x =13
\(\left(x-35\right)-120=0\)
\(=>x-35=120\)
\(=>x=120+35\)
\(=>x=155\)
a, (x - 35) - 120 = 0
=> x - 35 = 120
=> x = 155
b, 124 + (118 - x) = 217
=> 118 - x = 93
=> x = 25
c, 156 - (x + 61) = 82
=> x + 61 = 74
=> x = 13
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a) 156 - (x + 61) = 82
x + 61 = 156 - 82 = 74
x = 74 - 61 = 13
b) 5(x + 35) = 515
x + 35 = 515 : 5 = 103
x = 103 - 35 = 68
c) x : 5 = x : 6
\(\frac{x}{5}-\frac{x}{6}=0\)
\(\frac{6x-5x}{30}=0\)=> x = 0
d) (x - 42)(x - 21) = 0
=> x - 42 = 0 hoặc x - 21 = 0 => x = 42 hoặc x = 21
e) 124 + (118 - x) = 2
118 - x = 2 - 124 = -122
x = 118 - (- 122) = 240