3.3^2^3
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a) \(\dfrac{2^4\cdot5^2\cdot7}{2^3\cdot5\cdot7^2\cdot11}=\dfrac{2^3\cdot5\cdot10\cdot7}{2^3\cdot5\cdot7\cdot77}=\dfrac{10}{77}\)
\(\dfrac{2^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot2^4\cdot5^3\cdot14}=\dfrac{2^3\cdot3\cdot5^3\cdot7\cdot3^2\cdot8}{3\cdot2^3\cdot2\cdot5^3\cdot14}=\dfrac{7\cdot3^2\cdot8}{2\cdot14}=\dfrac{63\cdot8}{2\cdot14}=18=\dfrac{1386}{77}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ƯCLN(2^3*3^a;2^b*3^5)=2^2*3^5 nên b=2 và a<=5
BCNN(2^3*3^a;2^2*3^5)=2^3*3^6 nên a=6
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$20,23-(2^3.3-21)^2:(-3)-23,24$
$=20,23-(24-21)^2:(-3)-23,24=20,23-3^2:(-3)-23,24$
$=20,23-(-3)-23,24=20,23+3-23,24=23,23-23,24=-0,01$
![](https://rs.olm.vn/images/avt/0.png?1311)
(x - 140) : 7 = 3^3 - 2^3 . 3
(x - 140) : 7 = 27 - 8 . 3
(x - 140) : 7 = 27 - 24
(x - 140) : 7 = 3
x - 140 = 3 . 7
x - 140 = 21
x = 21 + 140
x = 161
(x-140):7=3^3-2^3.3
(x-140):7=27-8.3
(x-140):7=27-24
(x-140):7=3
x-140 =3.7
x-140 = 21
x =21+140
x = 161
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\(5^6:5^3+3^3.3^2\)
\(=5^2+3^3.3^2\)
\(=5^2+3^5\)
\(=25+243\)
\(=268\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3.3^2^3 = 19683
19683