tim x: 1/5 x 7+1/7x9+...+1/X(x+2)=7/95
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
N
2
T
29 tháng 8 2018
\(x\times7\times9=\frac{10}{3}\)
\(x\times63=\frac{10}{3}\)
\(x=\frac{10}{3}:63\)
\(x=\frac{10}{189}\)
\(x\times\frac{2}{5}=\frac{1}{4}\times4\)
\(x\times\frac{2}{5}=1\)
\(x=1:\frac{2}{5}\)
\(x=\frac{5}{2}\)
\(x:\frac{1}{7}=\frac{1}{2}+\frac{3}{5}\)
\(x:\frac{1}{7}=\frac{11}{10}\)
\(x=\frac{11}{10}\times\frac{1}{7}\)
\(x=\frac{11}{70}\)
\(x:\frac{8}{9}=\frac{2}{9}+5\)
\(x:\frac{8}{9}=\frac{47}{9}\)
\(x=\frac{47}{9}\times\frac{8}{9}\)
\(x=\frac{376}{81}\)
29 tháng 8 2018
a)X x 7x9 = 10/3 b) X x 2/5 =1/4 x4 c)X : 1/7 = 1/2 + 3/5
X \(\times\)7=\(\frac{10}{3}\div9\) X\(\times\frac{2}{5}=1\) \(x\div\frac{1}{7}=\frac{11}{10}\)
X\(\times\)7=\(\frac{10}{27}\) X\(=1\div\frac{2}{5}\) \(x=\frac{11}{10}\times\frac{1}{7}\)
X=\(\frac{10}{27}\)\(\div7\) X\(=\frac{5}{2}\) \(x=\frac{11}{70}\)
X=\(\frac{10}{198}\)
d)X : 8/9 =2/9 +5
\(x\div\frac{8}{9}=\frac{47}{9}\)
\(x=\frac{47}{9}\times\frac{8}{9}\)
\(x=\frac{376}{81}\)
8 tháng 2 2022
6: =>x=9/10+1/5=9/10+2/10=11/10
7: =>x=3/8-5/12=36/96-40/96=-1/24
8: =>x=7/6-5/4=14/12-15/12=-1/12
9: =>x=1/35+2/7=1/35+10/35=11/35
10: =>x=2/7-7/10=20/70-49/70=-29/70
O
3 tháng 5 2022
a) \(\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{2}{5}\right)\times\left(1-\dfrac{2}{7}\right)\times\left(1-\dfrac{2}{9}\right)\)
\(=\left(\dfrac{3}{3}-\dfrac{1}{3}\right)\times\left(\dfrac{5}{5}-\dfrac{2}{5}\right)\times\left(\dfrac{7}{7}-\dfrac{2}{7}\right)\times\left(\dfrac{9}{9}-\dfrac{2}{9}\right)\)
\(=\dfrac{2}{3}\times\dfrac{3}{5}\times\dfrac{5}{7}\times\dfrac{7}{9}\)
\(=\dfrac{2\times3\times5\times7}{3\times5\times7\times9}\)
\(=\dfrac{2}{9}\)
b) \(\dfrac{1}{1\times3}+\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}\)
\(=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}\)
\(=1-\dfrac{1}{9}\)
\(=\dfrac{9}{9}-\dfrac{1}{9}\)
\(=\dfrac{8}{9}\)
O
3 tháng 5 2022
Sửa câu b)
b) \(\dfrac{1}{1\times3}+\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}\)
Đặt \(A=\dfrac{1}{1\times3}+\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}\)
\(2A=\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+\dfrac{2}{7\times9}\)
\(2A=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}\)
\(2A=1-\dfrac{1}{9}\)
\(2A=\dfrac{9}{9}-\dfrac{1}{9}\)
\(2A=\dfrac{8}{9}\)
\(A=\dfrac{8}{9}:2\)
\(A=\dfrac{8}{18}\)
\(A=\dfrac{4}{9}\)
Vậy : \(\dfrac{1}{1\times3}+\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}=\dfrac{4}{9}\)
8 tháng 2 2022
1: =>x=-5/3-1/2=-13/6
2: =>x=1/3-3/5=-4/15
4: =>x=-7/9+4/3=-7/9+12/9=5/9
5: =>x=5/6-7/3=5/6-14/6=-9/6=-3/2
6: =>x=9/10+1/5=11/10
7: =>x=3/8-5/12=36/96-40/96=-1/24
8: Đề sai rồi bạn
5 tháng 8 2016
a, (x + 9) + (x - 2) + (x + 7) + (x - 4) + (x + 5) + (x - 6) + (x + 3) + (x - 8) + (x + 1) = 95
x + 9 + x - 2 + x + 7 + x - 4 + x + 5 + x - 6 + x + 3 + x - 8 + x + 1 = 95
9x + 9 - 2 + 7 - 4 + 5 - 6 + 3 - 8 + 1 = 95
9x + 5 = 95
9x = 95 - 5
9x = 90
x = 90 : 9
x = 10
Vậy x = 10
b, {[(x : 2) - 1/2 ] : 4 - 1/4 } : 5 = 5 + 1/5
{[(x : 2) - 1/2 ] : 4 - 1/4 } : 5 = 26/5
{[(x : 2) - 1/2 ] : 4 - 1/4 } = 26/5 x 5
[(x : 2) - 1/2 ] : 4 - 1/4 = 26
[(x : 2) - 1/2 ] : 4 = 26 + 1/4
[(x : 2) - 1/2 ] : 4 = 105/4
(x : 2) - 1/2 = 105/4 x 4
(x : 2) - 1/2 = 105
x : 2 = 105 + 1/2
x : 2 = 211/2
x = 211/2 x 2
x = 211
Vậy x = 211
NH
0
NH
1
AH
26 tháng 9 2016
1 / 5 + x = 3 / 7 + 1 / 3
1 / 5 + x = 16 /21
x = 16 / 21 - 1 / 5
x = 59 / 105
x - 1 / 2 = 2 / 3 - 1 / 5
x - 1 / 2 = 7 / 15
x = 7 / 15 + 1 / 2
x = 29 / 30
3 / 5 * x = 2 / 7+ 1 / 4
3 / 5 * x = 15 / 28
x = 15 / 28 : 3 / 5
x = 25 / 28
7 / 8 : x = 1 / 6 * 2 / 3
7 / 8 : x = 1 / 9
x = 7 / 8 : 1 / 9
x = 63 / 8
Đặt VT=A
\(2A=\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{x\left(x+2\right)}\)
\(2A=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+2}\)
\(A=\left(\frac{1}{5}-\frac{1}{x+2}\right):2\)
Thay A vào VT ta đc:
\(\left(\frac{1}{5}-\frac{1}{x+2}\right):2=\frac{7}{95}\)
\(\frac{1}{5}-\frac{1}{x+2}=\frac{14}{95}\)
\(\frac{1}{x+2}=\frac{1}{19}\)
\(\Rightarrow x+2=19\)
\(\Rightarrow x=17\)
\(\text{Đặt VT=A }\)
\(2A=\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{x\left(x+2\right)}\)
\(2A=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+2}\)
\(A=\left(\frac{1}{5}-\frac{1}{x+2}\right):2\)
\(\text{Thay A vào VT ta đc: }\)
\(\left(\frac{1}{5}-\frac{1}{x+2}\right):2=\frac{7}{95}\)
\(\frac{1}{5}-\frac{1}{x+2}=\frac{14}{95}\)
\(\frac{1}{x+2}=\frac{1}{19}\)
\(\Rightarrow x+2=19\)
\(\Rightarrow x=17\)