-10-(x30^2-|y-5|
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a: \(=2.125+5.375+7.15+6.85+7.5\)
=7,5+14+7,5
=15+14=29
b: \(\Leftrightarrow\left(\dfrac{4}{5}\cdot\dfrac{5}{6}+\dfrac{1}{5}\cdot x\right)\cdot30=60\)
=>(2/3+1/5x)=2
=>1/5x=2-2/3=4/3
=>x=4/3*5=20/3
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Vậy
80,9 x 10 = 8,09 x100
13,5 x50 > 1,35 x 100
9,07 x30 < 90,7 x30
4,897 x100 < 49,87 x100
3,67 x 1000 < 367x100
0456x1000 > 4,56 x10
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a) y x (27 + 30 + 43 ) = 500
y x 100 = 500
y = 5
b) tương tự: y x 10 = 9600
y = 960
a)y x 27 + y x 30 + y x 43 = 500
y = 500 : (27 + 30 +43)
y = 500 : 100
y = 5
b)y x 2 + y x 3 + y x 5 = 9600
y = 9600 : (2 + 3 + 5)
y=9600 : 10
y = 960
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\left(x-5\right).30\%=\dfrac{20x}{100}+5\Rightarrow\left(x-5\right).\dfrac{3}{10}=\dfrac{x}{5}+5\)
\(\Rightarrow\dfrac{3}{10}x+\dfrac{3}{2}=\dfrac{x}{5}+5\Rightarrow\dfrac{3}{10}x-\dfrac{x}{5}=5-\dfrac{3}{2}\)
\(\Rightarrow x\left(\dfrac{3}{10}-\dfrac{1}{5}\right)=\dfrac{7}{2}\Rightarrow\dfrac{1}{10}x=\dfrac{7}{2}\Rightarrow x=35\)
b, \(\dfrac{x+3}{x-2}\in Z\)
Ta có: \(\dfrac{x-2+5}{x-2}=\dfrac{x-2}{x-2}+\dfrac{5}{x-2}=1+\dfrac{5}{x-2}\)
Để \(\dfrac{x+3}{x-2}\in Z\Leftrightarrow\dfrac{5}{x-2}\Leftrightarrow5⋮\left(x-2\right)\Rightarrow\left(x-2\right)\in U\left(5\right)\)
\(\Rightarrow\left(x-2\right)\in\left\{1;5\right\}\Rightarrow x\in\left\{-1;3\right\}\)
Kiến thức lâu k học :> sai gì bỏ qua giùm :<<
Bạn ghi lại đề nhé. Sao có dấu "(" mà ko có dấu ")"