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14 tháng 2 2016

j mà  nhìu zu zậy làm bao giờ mới xong

14 tháng 2 2016

Ủng hộ mk đi các bạn
 

12 tháng 4 2015

a)             \(A=\frac{1}{5}+\frac{1}{45}+\frac{1}{117}+\frac{1}{221}+\frac{1}{357}+\frac{1}{525}\)

                  \(\Rightarrow A=\frac{1}{1.5}+\frac{1}{5.9}+\frac{1}{9.13}+...+\frac{1}{21.25}\)

                      \(\Rightarrow4A=\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{21.25}\)

                            \(4A=\frac{1}{1}-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+...+\frac{1}{21}-\frac{1}{25}\)

                             \(4A=\frac{1}{1}-\frac{1}{25}=\frac{24}{25}\)

                            \(\Rightarrow A=\frac{24}{25}\div4=\frac{6}{25}

22 tháng 11 2016

Xét vế trái: 1-1/2+1/3-1/4+1/5-1/6+...+1/199-1/200

=(1+1/3+1/5+..+1/199)-(1/2+1/4+..+1/200)

=(1+1/2+1/3+1/4+1/5+...+1/199+1/200)-2.(1/2+1/4+..+1/200)

=1+1/2+1/3+1/4+1/5+..+1/199+1/200-1-1/2-...-1/100

=1/101+1/102+1/103+...1/200

Vậy vế trái bằng vế phải

18 tháng 3 2021

i

help me

2 tháng 8 2023

\(A=\dfrac{1}{101}+\dfrac{1}{102}+\dfrac{1}{103}+...+\dfrac{1}{199}+\dfrac{1}{120}\left(a\right)\)

\(\Rightarrow A=\left(\dfrac{1}{101}+\dfrac{1}{102}+...\dfrac{1}{125}\right)+\left(\dfrac{1}{126}+\dfrac{1}{127}+...\dfrac{1}{150}\right)+\left(\dfrac{1}{151}+\dfrac{1}{152}+...\dfrac{1}{175}\right)+\left(\dfrac{1}{176}+\dfrac{1}{177}+...\dfrac{1}{200}\right)\)

\(\Rightarrow A>25.\dfrac{1}{125}+25.\dfrac{1}{150}+25.\dfrac{1}{175}+25.\dfrac{1}{200}\)

\(\Rightarrow A>\dfrac{1}{5}+\dfrac{1}{6}+\dfrac{1}{7}+\dfrac{1}{8}\)

\(\Rightarrow A>\dfrac{168+140+120+105}{840}=\dfrac{533}{840}>\dfrac{5}{8}\left(\dfrac{533}{840}>\dfrac{525}{840}\right)\)

\(\Rightarrow A>\dfrac{5}{8}\left(1\right)\)

\(\left(a\right)\Rightarrow A=\left(\dfrac{1}{101}+...\dfrac{1}{120}\right)+\left(\dfrac{1}{121}+...\dfrac{1}{140}\right)+\left(\dfrac{1}{141}+...\dfrac{1}{160}\right)+\left(\dfrac{1}{161}+...\dfrac{1}{180}\right)+\left(\dfrac{1}{181}+...\dfrac{1}{200}\right)\)

\(\Rightarrow A< 20.\dfrac{1}{100}+20.\dfrac{1}{120}+20.\dfrac{1}{140}+20.\dfrac{1}{160}+20.\dfrac{1}{180}\)

\(\Rightarrow A< \dfrac{1}{5}+\dfrac{1}{6}+\dfrac{1}{7}+\dfrac{1}{8}+\dfrac{1}{9}\)

\(\Rightarrow A< \dfrac{1}{5}+\dfrac{1}{6}+\dfrac{1}{7}+\dfrac{1}{8}+\dfrac{504+420+360+315+280}{2520}=\dfrac{1879}{2520}< \dfrac{3}{4}\left(\dfrac{1879}{2520}< \dfrac{1890}{2520}\right)\)

\(\Rightarrow A< \dfrac{3}{4}\left(2\right)\)

\(\left(1\right),\left(2\right)\Rightarrow\dfrac{5}{8}< A< \dfrac{3}{4}\left(dpcm\right)\)

a: A>1/150*50+1/200*50=1/3+1/4=7/12

b: A>7/12

7/12>5/8

=>A>5/8