a) -12/13 χ -5=6 1/13
K
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KV
19 tháng 8 2023
a) (x - 15) × 7 - 270 : 45 = 169
(x - 15) × 7 - 6 = 169
(x - 15) × 7 = 169 + 6
(x - 15) × 7 = 175
x - 15 = 175 : 7
x - 15 = 25
x = 25 + 15
x = 40
b) [(4x + 28) × 3 + 55] : 5 = 35
(4x + 28) × 3 + 55 = 35 × 5
(4x + 28) × 3 + 55 = 175
(4x + 28) × 3 = 175 - 55
(4x + 28) × 3 = 120
4x + 28 = 120 : 3
4x + 28 = 40
4x = 40 - 28
4x = 12
x = 12 : 4
x = 3
c) (455 × x : 2 × 6) : 5 = 31
455 × x : 2 × 6 = 31 × 5
455 × x : 2 × 6 = 155
x × 455 : 2 × 6 = 155
x × 1365 = 155
x = 155 : 1365
x = 31/273
d) 128 × x - 12 × x - 16 × x = 520800
(128 - 12 - 16) × x = 520800
100 × x = 520800
x = 520800 : 100
x = 5208
KV
19 tháng 8 2023
e) (x × 0,25 + 2022) × 2023 = (50 + 2022) × 2023
(x × 0,25 + 2022) × 2023 = 2072 × 2023
(x × 0,25 + 2022) × 2023 = 4191656
x × 0,25 + 2022 = 4191656 : 2023
x × 0,25 + 2022 = 2072
x × 0,25 = 2072 - 2022
x × 0,25 = 50
x = 50 : 0,25
x = 200
f) 4 × x + 100 = x + 280
4 × x - x = 280 - 100
(4 - 1) × x = 180
3 × x = 180
x = 180 : 3
x = 60
g) (x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 7450
x + 1 + x + 2 + x + 3 + ... + x + 100 = 7450
100 × x + 100 × 101 : 2 = 7450
100 × x + 5050 = 7450
100 × x = 7450 - 5050
100 × x = 2400
x = 2400 : 100
x = 24
NT
Nguyễn thành Đạt
CTVHS
15 tháng 9 2023
Bài 1 :
a) A= (1;2;3;4;5)
b) B= ( 63;64;65;66;67;68;69;70)
Bài 2 :
a) 10x-5 = 11.5-10
10x-5 = 55-10
10x=45+5
10x=50
x=5
b) 27-3x=9.2-3
27-3x = 18-3
27-3x=15
3x=27-15
3x=12
x=4
c) 4x-15=12:12
4x-15=1
4x=16
x=4
d) 2+13x=14.2
13x=28-2
13x=26
x=2
ND
Nguyễn Đăng Nhân
CTVHS
15 tháng 9 2023
a) \(10x-5=45\)
\(10x=40\)
\(x=4\)
b) \(27-3x=15\)
\(3x=27-15=12\)
\(x=\dfrac{12}{3}=4\)
c) \(4x-15=1\)
\(4x=16\)
\(x=\dfrac{16}{4}=4\)
d) \(2+13x=28\)
\(13x=26\)
\(x=\dfrac{26}{13}=2\)
BH
12 tháng 8 2016
- Đề bài: 2.(χ+3)-13=11
- Giải:
2.(χ+3)-13=11
2.( x + 3) = 11 + 13
2.(x + 3 ) = 24
x + 3= 24 :2
x + 3 = 12
x = 12- 3
x= 9
- Vậy giá trị của x = 9
12 tháng 8 2016
\(2\left(x+3\right)-13=11\)
\(\Leftrightarrow2\left(x+3\right)=24\)
\(\Leftrightarrow x+3=12\)
\(\Leftrightarrow x=9\)
10 tháng 8 2022
1.3.77−1+3.7.99−3+7.9.1313−7+9.13.1515−9+\frac{19-13}{13.15.19}+13.15.1919−13
=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31−3.71+3.71−7.91+7.91−9.131+9.131−13.151+13.151−15.191
=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31−15.191=28595−2851=28594
b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61.(1.3.76+3.7.96+7.9.136+9.13.156+13.15.196)
làm giống như trên
c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81.(1.2.31+2.3.41+3.4.51+...+48.49.501)
=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161.(1.2.32+2.3.42+3.4.52+...+48.49.502)
=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161.(1.2.33−1+2.3.44−2+3.4.55−3+...+48.49.5050−48)
=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161.(1.21−2.31+2.31−3.41+3.41−4.51+...+48.491−49.501)
=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161.(21−24501)=161.(24501225−24501)=4900153
d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75.(1.5.87+5.8.127+8.12.157+...+33.36.407)
=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75.(1.5.88−1+5.8.1212−5+8.12.1515−8+...+33.36.4040−33)
=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75.(1.51−5.81+5.81−8.121+8.121−12.151+...+33.361−36.401)
=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75.(51−14401)=75.(1440288−14401)=28841
P/S: . là nhân nha
VT
20 tháng 8 2017
\(a,=\frac{7-1}{1.3.7}+\frac{9-3}{3.7.9}+\frac{13-7}{7.9.13}+\frac{15-9}{9.13.15}\)\(+\frac{19-13}{13.15.19}\)
\(=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}\)
\(=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}\)
\(b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)\)
làm giống như trên
\(c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}\)
\(d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}\)
P/S: . là nhân nha
NN
1
16 tháng 4 2022
câu a) lấy mẫu số chung cộng với nhau
câu b) lấy 1 để ngoài nhân r 1/2-1/3 rồi tương tự
ZS
0
Đề bài yêu cầu gì?