134-2×{156-6×[54-2×(9+6)]}×x=86
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
134-2.{156-6.[54-2.(9+6)]}.x=86
2.{156-6.[54-2.15]}.x=134-86
2.{156-6.[54-30]}.x=48
2.{[156-6.24]}.x=48
2.{[156-144]}.x=48
2.{12}.x=48
24.x=48
x=48:24
x=2
Vậy x=2
Chúc bn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
134-2.{156-6.[54-2.(9+6)]}.x=86
<=>134-2.{156-6.[54-2.15]}.x=86
<=>134-2.{156-6.24}.x=86
<=>134-2.12.x=86
<=>134-24.x=86
<=>24.x=134-86
<=>24.x=48
<=>x=48:24
<=>x=2
Vậy...
k mik nhé
Thanks
![](https://rs.olm.vn/images/avt/0.png?1311)
134 - 2 . {156 - 6[54 - 2(9 + 6)]} . x = 86
134 - 2 . { 156 - 6 [ 54 - 2 . 15 ) ] } . x = 86
134 - 2 . { 156 - 6 [ 54 - 30 ] } . x = 86
134 - 2 . { 156 - 6 . 24 } . x = 86
134 - 2 . { 156 - 144 } . x = 86
134 - 2 . 21 . x = 86
2 . 21 . x = 134 - 86
2 . 21 . x = 48
21 . x = 48 : 2
21 . x = 24
x = 24 : 21
x = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
42 -(2x + 32) + 12 :2 =6
42 - 2x - 32 + 6 = 6
42 - 2x - 32 = 0
42 - 2x = 32
2x = 42 - 32 = 10
x = 5
134 - 2 . {156 - 6.[54 -2.(9+6) ] } x = 86
134 - 2.{ 156 - 6.[54 - 2 . 15 ]} x = 86
134 - 2.{ 156 - 6 . 24} x = 86
134 - 2. 12 .x = 86
134 - 24x = 86
24x = 48
x = 2
\(42-\left(2x+32\right)+12:2=6\)
\(\Rightarrow42-2x-32=0\)
\(\Rightarrow2x=10\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
134 - 2.{ 156 - 6 .[ 54 - 2 .( 9 + 6 )]} . x = 86
134 - 2.{ 156 - 6 .[ 54 - 2 . 15 ]} . x = 86
134 - 2.{ 156 - 6 .[ 54 - 30 ]} . x= 86
134 - 2.{ 156 - 6 . 24 } . x = 86
134 - 2.{ 156 - 144 } . x = 86
134 - 2 . 12 . x = 86
134 - 24 . x = 86
24 . x = 134 - 86
24 . x = 48
x = 48 : 24
x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
ko viết lại đề
=> \(2x\left\{156-6\left[54-2.15\right]\right\}=134-86\)
=> \(2x\left\{156-6\left[54-30\right]\right\}=48\)
=> \(2x\left\{156-6.24\right\}=48\)
=> \(2x\left\{156-144\right\}=48\)
=> \(2x.12=48\)
=> \(24x=48\)
=> \(x=48:24=2\)
Vậy \(x\in\left\{2\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5.\left[225-\left(x-10\right)-125\right]=0\)
\(225-\left(x-10\right)-125=0:5\)
\(225-\left(x-10\right)-125=0\)
\(\left(x-10\right)-125=225-0\)
\(\left(x-10\right)-125=225\)
\(x-10=225+125\)
\(x-10=350\)
Mấy bài này làm theo thứ tứ trái sang phải, nhân chia trc cộng trừ sau thoi mà :>>>?