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a) $C_xH_yO_z + (x + \dfrac{y}{4} - \dfrac{z}{2})O_2 \xrightarrow{t^o} xCO_2 + \dfrac{y}{2}H_2O$
b)
$Cu + 2H_2SO_4 \to CuSO_4 + SO_2 + H_2O$
c)
$2KMnO_4 + 16HCl \to 2KCl + 2MnCl_2 + 5Cl_2 +8H_2O$
d)
$Fe_3O_4 + 8HCl \to FeCl_2 + 2FeCl_3 + 4H_2O$
e)
$2Ag + 2H_2SO_4 \to Ag_2SO_4 + SO_2 + 2H_2O$
\(Fe+S\underrightarrow{t^o}FeS\)
\(2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\)
\(2Cu+O_2\underrightarrow{t^o}2CuO\)
\(Mg+CuSO_4\rightarrow MgSO_4+Cu\downarrow\)
\(Ag+FeCl_2\rightarrow X\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Mg+2HCl\rightarrow MgCl_2+H_2\uparrow\)
2KClO3 --to--> 2KCl + 3O2
Al2O3 + 3H2SO4 --> Al2(SO4)3 + 3H2O
2C2H6 + 7O2 --t0--> 4CO2 + 6H2O
Fe2O3 + 6HCl --> 2FeCl3 + 3H2O
bài 1
câu a:
Mn02 + 4HCl --> MnCl2 + Cl2 + 2H20
Cl2 + H2 -->t° ánh sáng 2HCl
4HCl + Mn02 --> MnCl2 + Cl2 + 2H20
Cl2 + 2Na -->t° 2NaCl
2NaCl -->điện phân nóng chảy 2Na + Cl2
câu b/
2KMnO4 + 16HCl (đ) -> 2KCl + 2MnCl2 + 5Cl2 + 8H2O (Đ.C Cl2)
Cl2 + KOH -> KCl + KClO3 + H2O
2KClO3 -> 2KCl + 3O2 (đ/c khí O2 lớp 8)
2KCl -> 2K + Cl2
Cl2 + H2O ->HCl + HClO
2HCl + Fe -> FeCl2 + H2
2FeCl2 + Cl2 -> 2FeCl3
FeCl3 + NaOH -> Fe(OH)3 + NaCl
câu c/
HCl ---> Cl2 ---> FeCl3 ---> NaCl ---> HCl ---> CuCl2 ---> AgCl
2HCl→Cl2+H2
3Cl2+2Fe→2FeCl3
3NaOH+FeCl3→3NaCl+Fe(OH)3
H2SO4+NaCl→HCl+NaHSO4
CuO+2HCl→2H2O+CuCl2
2AgNO3+CuCl2→2AgCl+Cu(NO3)2
Bài 2:
CTHH: MO
\(n_{MO}=\dfrac{15,3}{M_M+16}\left(mol\right)\)
PTHH: MO + 2HCl --> MCl2 + H2O
=> \(n_{MCl_2}=\dfrac{15,3}{M_M+16}\left(mol\right)\)
=> \(\dfrac{15,3}{M_M+16}\left(M_M+71\right)=20,8\)
=> MM = 137 (g/mol)
=> M là Ba (Bari)
\(n_{BaO}=\dfrac{15,3}{153}=0,1\left(mol\right)\)
PTHH: BaO + 2HCl --> BaCl2 + H2O
0,1-->0,2
=> mHCl = 0,2.36,5 = 7,3 (g)
=> \(m_{ddHCl}=\dfrac{7,3.100}{18,25}=40\left(g\right)\)
1.
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
\(H_2+Cl_2\underrightarrow{^{as}}2HCl\)
\(NaOH+HCl\rightarrow NaCl+H_2O\)
\(2NaCl\underrightarrow{^{đpnc}}2Na+Cl_2\)
\(4Cl_2+H_2S+4H_2O\rightarrow8HCl+H_2SO_4\)
\(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)
2.
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(6KOH+3Cl_2\rightarrow5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
\(Fe+\frac{3}{2}Cl_2\underrightarrow{^{to}}FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\)
\(2KCl+2H_2O\underrightarrow{^{đpmn}}2KOH+Cl_2+H_2\)
3.
\(BaCl_2\underrightarrow{^{đpnc}}Ba+Cl_2\)
\(Cl_2+H_2\underrightarrow{^{as}}2HCl\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(2FeCl_2+3Cl_2\rightarrow2FeCl_3\)
\(3Ba\left(OH\right)_2+2FeCl_3\rightarrow3BaCl_2+2Fe\left(OH\right)_3\)
\(BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl\)
4.
\(C_2H_2+Cl_2\rightarrow2C+2HCl\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\)
\(2KCl+2H_2O\underrightarrow{^{đpmn}}2KOH+H_2+Cl_2\)
\(3Cl_2+6KOH\rightarrow5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
5.
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
\(2Fe+3Cl_2\rightarrow2FeCl_3\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+AgNO_3\rightarrow Cu\left(NO_3\right)_2+2AgCl\)
6.
\(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+H_2O\)
\(6KOH+3Cl_2\rightarrow5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
\(2KCl\underrightarrow{^{đpnc}}2K+Cl_2\)
\(Cl_2+Ca\left(OH\right)_2\rightarrow CaOCl_2+H_2O\)
1. MnO2 +4HCl→ Cl2+MnCl2+4H2O
Cl2+2H2→ 2HCl
HCl+Na2O→ NaCl+H2O
2NaCl → Cl2+2Na
2Cl2+2H2O+CO2→ H2SO4 +4HCl
H2SO4+BaCl2→ 2HCl+BaSO4
2. 2KMnO4 +16HCl→ 5Cl2+8H2O+2KCl+2MnCl2
2Cl2+6KOH→ KClO3 +5KCl+3H2O
KClO3+6HCl→ 3Cl2+KCl+3H2O
3Cl2+2Fe→2 FeCl3
FeCl3+3KOH→ 3KCl +Fe(OH)3
2KCl+2H2O→ KOH+Cl2+2H2O
3. BaCl2 → Cl2+Ba
Cl2+2H2→ 2HCl
2HCl+Fe→ FeCl2+H2
2FeCl2+Cl2→ 2FeCl3
2FeCl3+3Ba(OH)2→ 3BaCl2+2Fe(OH)3
BaCl2+H2SO4→ 2HCl+BaSO4
Mỏi tay rồi :((
4HCl+MnO2-->MnCl2+2H2O+Cl2
3Cl2+2Fe-->2FeCl3
FeCl3+3NaOH-->3NaCl+Fe(OH)3
2NaCl+H2SO4-->Na2SO4+2HCl
2HCl+Cuo-->CuCl2+H2O
CuCl2+2AgNO3-->2AgCl+Cu(NO3)2
3)
3Cl2+6KOH→3H2O+5KCl+KClO3
2KClO3→2KCl+3O2
2KCl+H2SO4→K2SO4+2HCl
16HCl+2KMnO4→5Cl2+8H2O+2KCl+2MnCl2
2Ca(OH)2+2Cl2→2H2O+CaCl2+Ca(ClO)2 e)a. 2KMnO4 + 16HCl (đ) -> 2KCl + 2MnCl2 + 5Cl2 + 8H2O (Đ.C Cl2)
Cl2 + KOH -> KCl + KClO3 + H2O
2KClO3 -> 2KCl + 3O2 (đ/c khí O2 lớp 8)
2KCl -> 2K + Cl2
Cl2 + H2O ->HCl + HClO
2HCl + Fe -> FeCl2 + H2
2FeCl2 + Cl2 -> 2FeCl3
FeCl3 + NaOH -> Fe(OH)3 + NaCl
a. NaCl → Cl2 → FeCl3 → NaCl → HCl → CuCl2 → AgCl.
2NaCl+2H2O-đp\mn->2NaOH+H2+Cl2
3Cl2+2Fe-to>2FeCl3
FeCl3+3NaOH->3NaCl+Fe(OH)3
2NaCl+H2SO4-to>Na2SO4+2HCl
2HCl+CuO->CuCl2+H2O
CuCl2+2AgNO3->2AgCl+Cu(NO3)2
\(a) 6HCl + KClO_3 \to KCl + 3Cl_2 + 3H_2O\\ b) Cu + \dfrac{1}{2}O_2 + 2HCl \to CuCl_2 + H_2O\\ c) CaO + H_2SO_4 \to CaSO_4 + H_2O\)