Question

[Đừng gọi tôi là Jung Hae Ri]

Viết khai triển Niutơn;

\(a,\left(\dfrac{1}{x}-\dfrac{x^2}{3}\right)^5\)

\(b,\left(\sqrt{2}x+1\right)^5\)

Answer 1

[Hồng Phúc]

a, \(\left(\dfrac{1}{x}-\dfrac{x^2}{3}\right)^5=\sum\limits^5_{k=0}C^k_5.\left(\dfrac{1}{x}\right)^{5-k}.\left(-\dfrac{x^2}{3}\right)^k=\sum\limits^5_{k=0}C^k_5.\left(-\dfrac{1}{3}\right)^k.x^{3k-5}\)

Answer 2

[Hồng Phúc]

b, \(\left(\sqrt{2}x+1\right)^5=\sum\limits^5_{k=0}C^k_5.\left(\sqrt{2}x\right)^k=\sum\limits^5_{k=0}C^k_5.\left(\sqrt{2}\right)^k.x^k\)