Tìm x: a)100 – 7 . (x – 5 ) = 58
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100 - 7 . ( x - 5 ) = 58
93 . x - 5 = 58
x - 5 =93 : 58
x - 5 = 1.6
x = 1.6 +5
x = 6.6
100-7.(x-5)=58
7.(x-5)=100-58
7.(x-5)=42
x-5=42:7
x-5=7
x=7+5
x=12
vậy x=12
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) 100-7(x-5)=58
=> 7(x-5)=42
=.> x-5 = 6
=> x=11
180-5(x+1)=30
=> 5(x+1)=150
=> x+1=30\
=> x=29
6x-5=613
=> 6x=618
=> x=103
a) \(100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
\(\Leftrightarrow x=11\)
b) \(180-5\left(x+1\right)=30\)
\(\Leftrightarrow5\left(x+1\right)=150\)
\(\Leftrightarrow x+1=30\)
\(\Leftrightarrow x=29\)
c) \(6x-5=613\)
\(\Leftrightarrow6x=618\)
\(\Leftrightarrow x=103\)
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\(a,565-\left(6x+70\right)=435\)
\(6x+70=565-435\)
\(6x+70=130\)
\(6x=130-70\)
\(6x=60\)
\(x=10\)
\(b,100-7\left(x-5\right)=58\)
\(100-7x+35=58\)
\(100-7x=58-35\)
\(100-7x=23\)
\(7x=100-23\)
\(7x=77\)
\(x=11\)
a, 565-(6x+70)=435
6x+70=565-435
6x+70=130
6x=130-70
6x=60
x=60:6
x=6
b, 100-7(x-5)=58
7(x-5)=100-58
7(x-5)=42
x-5=42:7
x-5=6
x=6+5
x=11
![](https://rs.olm.vn/images/avt/0.png?1311)
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a. 348 : x = 12
x = 348 : 12
x = 29
b. 9x - 7 = 119
9x = 119 + 7
9x = 126
x = 126 : 9
x = 14
c. 100 - 7 . ( x - 5 ) = 58
7 . ( x - 5 ) = 100 - 58
7 . ( x - 5 ) = 42
x - 5 = 42 : 7
x - 5 = 6
x = 6 + 5
x = 11
d. x không thuộc số tự nhiên
a)348:x=12
x=348:12
x=29
b)9x-7=119
9x=119+7
9x=126
x=126:9
x=14
c)100-7.(x-5)=58
7.(x-5)=100-58
7.(x-5)=42
x-5=42:7
x-5=6
x=6+5
x=11
d)2x-2.23=64
2x-2.8=64
2x-16=64
2x=64+16
2x=80
đề sai
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![](https://rs.olm.vn/images/avt/0.png?1311)
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a. 25,97 + 6,54 + 103,46
= 25,97 + (6,54+103,46)
= 25,97+110
= 135,97
b. 50% + 7/12-1/2
= 1/2+7/12-1/2
= (1/2-1/2)+7/12
= 0+7/12
= 7/12
c. 2015.65 + 2015.45 - 2015.10
= 2015. (65+45-10)
= 2015.100
= 201500
2.a.2/3.x+3/4=3
=> 2/3.x=3-3/4
=> 2/3.x=9/4
=> x=9/4:2/3
=> x=9/4.3/2
=> x=27/8
b. 100-7(x-5)=58
=> 7(x-5)=100-58
=> 7(x-5)=42
=> x-5=42:7
=> x-5=6
=> x=6+5
=> x=11
c. x+1/3=7/26 x 13/6
=> x+1/3 = 7/12
=> x=7/12-1/3
=> x=7/12-4/12
=> x=3/12
=> x=1/4
![](https://rs.olm.vn/images/avt/0.png?1311)
a: Ta có: \(100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
hay x=11
b: Ta có: \(12\left(x-1\right):3=4^3+2^3\)
\(\Leftrightarrow12\left(x-1\right)=216\)
\(\Leftrightarrow x-1=18\)
hay x=19
a. x = 8