Tìm x b. 9 × ( x + 5 ) = 729
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b. 9 × ( x + 5) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 - 5
x = 76
![](https://rs.olm.vn/images/avt/0.png?1311)
b. 9 × ( x + 5 ) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 – 5
x =76
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (9458-x)x5=41195 b) (9x x)x6=23490
9458-x =41195:5 9 x x =23490:6
9458-x =8239 9 x x =3916
x=9458-8239 x = 3915:9
x=1219 x=435
c)9x(x+5)=729
x+5=729:9
x+5=81
x=81-5
x=76 k mk nha
a) (9458 - X) x 5 = 41195
9458 - X = 41195 : 5
9458 - X = 8239
X = 9458 - 8239
X = 1219
b) (9 x X) x 6 = 23490
9 x X = 23490 : 6
9 x X = 3915
X = 3915 : 9
X = 435
c) 9 x (X + 5) = 729
X + 5 = 729 : 9
X + 5 = 81
X = 81 - 5
X = 76
![](https://rs.olm.vn/images/avt/0.png?1311)
a, x-13=184:8
x-13=23
x=23+13
x=36
Vậy x=36
b,x:7=833:7
x:7=119
x=119x7
x=833
Vậy x=833
c, x+5=729:9
x+5=81
x=81-5
x=76
Vậy x=76
d,50-(17-x)=36
17-x=50-36
17-x=14
x=17-14
x=3
Vậy x=3
Hok tốt
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a) (2x)5 : 43 = 815 => 25x = 815.43 = (23)15.(22)3 = 245.26 = 251 => 5x = 51 => x = 10,2
b) (32)x .93 = 2439 => 32x = 2439 : 93 = (35)9 : (32)3 = 345 : 36 = 339 => 2x = 39 => x = 19,5
c) (1/125)3.5x = 255 => 5x = 255 : (1/125)3 = (52)5 : (1/53)3 = 510 : (5-3)3 = 510 : 5-9 = 519 => x = 19
d) 1/81 : 3x = 1/729 => 3x = 1/81 : 1/729 = 1/34.729 = 3-4.36 = 32 => x = 2
e) (5x - 2)4 = 168 = (162)4 = 2564
=> 5x - 2 = -256 ; 256 => 5x = -254 ; 258 => x = -50,8 ; 51,6
P/S : Thay x = 10,2 vào câu a , x = 19,5 vào câu b sẽ thấy điều hư cấu : 210,2 và 919,5.Ko thể tính được giá trị của 2 lũy thừa này.
![](https://rs.olm.vn/images/avt/0.png?1311)
`Answer:`
\(\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+...+\left(x+\frac{1}{729}\right)=\frac{4209}{729}\)
\(\Leftrightarrow\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{3^2}\right)+\left(x+\frac{1}{3^3}\right)+...+\left(x+\frac{1}{3^6}\right)=\frac{4209}{729}\)
\(\Leftrightarrow6x+\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)=\frac{4209}{729}\text{(*)}\)
Đặt \(N=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\)
\(\Leftrightarrow3N=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^5}\)
\(\Leftrightarrow3N-N=\left(1+\frac{1}{3}+\frac{1}{3^2}+..+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)\)
\(\Leftrightarrow2N=1-\frac{1}{3^6}\)
\(\Leftrightarrow2N=\frac{728}{729}\)
\(\Leftrightarrow N=\frac{364}{729}\)
\(\text{(*)}\Leftrightarrow6x+\frac{364}{729}=\frac{4209}{729}\)
\(\Leftrightarrow6x=\frac{3845}{729}\)
\(\Leftrightarrow x=\frac{3845}{4374}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)x*53=55
=>x*125=3125
=>x=3125:125
=>x=25
b) (x+1)*34=36
=>(x+1)*81=729
=>x+1=729:81
=>x+1=9
=>x=9-1
=>x=8
c) 9x-1=729
Mà:93=729
=> 9x-1=93
=>x-1=3
=>x=3+1
=>x=4
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{x^7}{81}=27\)
=> x7 = 27.81
=> x7 = 33.34
=> x7 = 37
=> x = 3
Vậy x = 3
b) \(\frac{x^8}{9}=729\)
=> x8 = 729.9
=> x8 = 36.32
=> x8 = 38 = (-3)8
=> \(x\in\left\{3;-3\right\}\)
Vậy \(x\in\left\{3;-3\right\}\)
b. 9 × ( x + 5 ) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 – 5
x =76