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a) \(\left(743-569\right)-\left(431-1257+996\right)\)
\(=743-569-431+1257-996\)
\(=\left(743+1257\right)-\left(569+431\right)-996\)
\(=2000-1000-996\)
\(=4\)
a. (2x - 612) + (-303) = 111-x
2x - 612 - 303 = 111 - x
2x - (612+303) = 111 - x
2x - 915 = 111 - x
2x + x = 111 + 915
3x = 1026
x = 1026 : 3
x = 342
vậy_____
`a,`
\((- 5) .x + 17 = - 23\)
`\Rightarrow (-5)x = -23 - 17`
`\Rightarrow (-5)x =-40`
`\Rightarrow x = (-40) \div (-5)`
`\Rightarrow x = 8`
Vậy,` x = 8`
`b,`
\(8 + 4x = - 24\)
`\Rightarrow 4x = -24 - 8`
`\Rightarrow 4x = -32`
`\Rightarrow x = -32 \div 4`
`\Rightarrow x = -8`
Vậy, `x = -8`
`c,`
\(32 – 12 + x = -10\)
`\Rightarrow 20 + x = -10`
`\Rightarrow x = -10 - 20`
`\Rightarrow x = -30`
Vậy, `x = -30`
`d,`
\(x – 87 + 13 = - 100\)
`\Rightarrow x - 87 = -100 - 13`
`\Rightarrow x - 87 = -113`
`\Rightarrow x = -113 + 87`
`\Rightarrow x = -26`
Vậy, `x = -26.`
b) \(\frac{x-11}{89}+\frac{x-13}{87}+\frac{x-15}{85}+\frac{x-17}{83}=4\)
\(=>\left(\frac{x-11}{89}-1\right)+\left(\frac{x-13}{87}-1\right)+\left(\frac{x-15}{85}-1\right)+\left(\frac{x-17}{83}-1\right)=0\)
\(=>\frac{x-100}{89}+\frac{x-100}{87}+\frac{x-100}{85}+\frac{x-100}{83}=0\)
\(=>\left(x-100\right)\left(\frac{1}{89}+\frac{1}{87}+\frac{1}{85}+\frac{1}{83}\right)=0\)
=> x-100 =0 => x=100
Vậy nghiệm là 100
ta có 0=\(\frac{x-11}{89}-1+\frac{x-13}{87}-1+\frac{x-15}{85}-1+\frac{x-17}{83}-1=0\)
0=\(\frac{x-11-89}{89}+\frac{x-13-87}{87}+\frac{x-15-85}{85}+\frac{x-17-83}{83}\)
0=\(\frac{x-100}{89}+\frac{x-100}{87}+\frac{x-100}{85}+\frac{x-100}{83}\)
0=(x-100)(\(\frac{1}{89}+\frac{1}{87}+\frac{1}{85}+\frac{1}{83}\))
vì \(\frac{1}{89}+\frac{1}{87}+\frac{1}{85}+\frac{1}{83}\)khác 0 suy ra x-100=0
x=100
Ta có :
\(\frac{x-3}{97}+\frac{x-27}{73}+\frac{x-67}{33}+\frac{x-73}{27}=4\)
\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)
\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)
Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}>0\) Nên \(x-100=0\)
\(\Leftrightarrow x=100\)
Vậy \(x=100\)
\(\Leftrightarrow\frac{x-3}{87}+\frac{x-27}{79}+\frac{x-67}{33}+\frac{x-73}{27}-4=0\)
\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)
\(\Leftrightarrow\left(\frac{x-3-97}{97}\right)+\left(\frac{x-27-73}{73}\right)+\left(\frac{x-67-33}{33}\right)+\left(\frac{x-73-27}{27}\right)=0\)
\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)
Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\ne0\)
\(\Rightarrow x-100=0\Leftrightarrow x=100\)
1/ Dùng qui tắc dấu ngoặc để tính
a/ (125 - 545) + (45 - 499 - 1125)
= 125-545 + 45-499-1125
= - (1125-125) - (545-45) - 499
= -1000 - 500 - 499
= -1500 - 499
= -1999
b/ (567 - 789) - (4567 - 2999 + 211)
= 567 - 789 - 4567 + 2999 - 211
= -(4567-567) - (789 + 211) + 2999
= -4000 - 1000 + 2999
= -5000 + 2999
= -2001
c/ -597 - (869 + 403) + (942 - 131)
= -597 - 869 - 403 + 942 - 131
= - (597 + 403) - (869 + 131) + 942
= -1000 - 1000 + 942
= -2000 + 942
= -1058
2/ Dùng qui tắc dấu ngoặc và chuyển vế để tìm x
a/ (565 - x) - 742 = -37
565 - x = -37 + 742
565 - x = 705
- x = 705 - 565
- x = 140
=> x = -140
vậy_____
b/ -569 - (213- x) = -400
- (213 - x) = -400 + 569
- (213 - x) = 169
=> 213 - x = -169
=> - x = -169 - 213
=> - x = -382
=> x = 382
vậy____
a: \(17464-17464:74-74\cdot158\)
\(=17464\cdot\left(1-\dfrac{1}{74}\right)-74\cdot158\)
\(=17464\cdot\dfrac{73}{74}-74\cdot158\)
\(=5536\)