(4x^2 -7x-50)^2 -16x^4 -56x^3 -49x^2 (ptđttnt bằng phương pháp nhóm hạng tử) GIÚP MÌNH NHANH NHÉ
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\(\left(4x^2-7x-50\right)^2-16x^4-56x^3-49x^2\)
\(=\left(4x^2-7x-50\right)^2-\left(4x^2\right)^2-2.4x^2.7x-\left(7x\right)^2\)
\(=\left(4x^2-7x-50\right)^2-\left(4x^2-7x\right)^2\)
\(=\left(4x^2-7x-50-4x^2+7x\right)\left(4x^2-7x-50+4x^2-7x\right)\)
\(=-50\left(8x^2-14x-50\right)\)
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\(=\left(4x^2-7x-50\right)^2-x^2\left(16x^2+56x+49\right)\)
\(=\left(4x^2-7x-50\right)^2-x^2\left(4x+7\right)^2\)
\(=\left(4x^2-7x-50-4x^2-7x\right)\left(4x^2-7x-50+4x^2+7x\right)\)
\(=\left(-14x-50\right)\left(8x^2-50\right)\)
\(=-4\left(7x+25\right)\left(2x-5\right)\left(2x+5\right)\)
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d) \(ax^2-5x^2-ax+5x+a-5=\left(ax^2-ax+a\right)+\left(-5x^2+5x-5\right)\)
\(=a\left(x^2-x+1\right)-5\left(x^2-x+1\right)=\left(a-5\right)\left(x^2-x+1\right)\)
e) \(ax-bx-2cx-2a+2b+4c=x\left(a-b-2c\right)-2\left(a-b-2c\right)\)
\(=\left(x-2\right)\left(a-b-2c\right)\)
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\(\left(4x^2-7x-50\right)^2-16x^4-56x^3-49x^2\)
\(\text{Phân tích thành nhân tử}\)
\(\left(-4\right)\left(2x-5\right)\left(7x+25\right)\)
\(x^m+3.y-x^m+1.Y^3-x^3.y^m+1+xy^m+3\)
\(\text{Phân tích thành nhân tử}\)
\(-\left(x^3y^m-xy^m-y^3-3y-4\right)\)
Câu 3 ko hiểu >o<
![](https://rs.olm.vn/images/avt/0.png?1311)
3x (5x2 - 2x - 1)