350-x=49+2(3x-21)
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a) \(5^x=100\)
\(5^x=10^2=\left(5\cdot2\right)^2\)
Sai đề
b) \(219-2^x=77\)
\(219-77=2^x\)
\(142=2^x\)??
c) \(18\left(x+27\right)=360\)
\(x+27=\frac{360}{18}=20\)
\(x=20-27=-7\)
d)\(\frac{\left(7x-140\right)}{21}=49\Rightarrow7x-140=49\cdot21=1029\)
\(7x=140+1029\)
\(7x=1169\Rightarrow x=\frac{1169}{7}=167\)
e) \(350+3^x=470\Rightarrow3^x=470-350=120\)
\(3^x=120????\)
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a) \(\left(3x-1\right)^2-\left(x+3\right)^2=0\)
\(=>\left(3x-1+x+3\right)\left(3x-1-x-3\right)=0\)
\(=>\left(4x+2\right)\left(2x-4\right)=0\)
\(=>4\left(2x+1\right)\left(x-2\right)=0\)
\(=>\orbr{\begin{cases}2x+1=0\\x-2=0\end{cases}}\)
\(=>\orbr{\begin{cases}x=-\frac{1}{2}\\x=2\end{cases}}\)
b)\(x^3-\frac{x}{49}=0=>x\left(x^2-\frac{1}{49}\right)=0=>x\left(x-\frac{1}{7}\right)\left(x+\frac{1}{7}\right)=0\)
\(=>x=0\)hoặc \(x=\frac{1}{7}\) hoặc \(x=-\frac{1}{7}\)
a)\(\(\left(3x-1\right)^2-\left(x+3\right)^2=0\)\)
\(\(\Leftrightarrow\left(3x-1-x-3\right)\left(3x-1+x+3\right)=0\)\)
\(\(\Leftrightarrow\left(2x-4\right)\left(4x+2\right)=0\)\)
\(\(\Leftrightarrow\orbr{\begin{cases}2x-4=0\\4x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-\frac{1}{2}\end{cases}}}\)\)
b)\(\(x^3-\frac{x}{49}=0\)\)
\(\(\Leftrightarrow\frac{49x^3-x}{49}=0\)\)
\(\(\Leftrightarrow x\left(49x^2-1\right)=0\)\)
\(\(\Leftrightarrow\orbr{\begin{cases}x=0\\49x^2-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\\left(7x-1\right)\left(7x+1\right)=0\end{cases}}}\)\)\
\(\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{7};x=-\frac{1}{7}\end{cases}}\)\)
c)\(\(x^2-7x+12=0\)\)
\(\(\Leftrightarrow\left(x-4\right)\left(x-3\right)=0\)\)
\(\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=3\end{cases}}}\)\)
d) \(\(4x^2-3x-1=0\)\)
\(\(\Leftrightarrow4x^2-4x+x-1=0\)\)
\(\(\Leftrightarrow4x\left(x-1\right)+\left(x-1\right)=0\)\)
\(\(\Leftrightarrow\left(x-1\right)\left(4x+1\right)=0\)\)
\(\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\4x+1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=-\frac{1}{4}\end{cases}}}\)\)
e) Tham khảo tại : [Toán 8]Giải phương trình | Cộng đồng học sinh Việt Nam - HOCMAI Forum
https://diendan.hocmai.vn/threads/toan-8-giai-phuong-trinh.290061/
_Y nguyệt_
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a) 3x - 21 = 27
3x = 27 + 21
3x= 48
x = 48 : 3
x= 16
b) -7 - x + 14 = 49
-7 - x = 49 - 14
-7 - x = 35
x = 35 : (-7)
x = -5
![](https://rs.olm.vn/images/avt/0.png?1311)
b: \(\Leftrightarrow\dfrac{7x+10}{x+1}\left(x^2-x-2-2x^2+3x+5\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(-x^2+2x+3\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(x^2-2x-3\right)=0\)
=>(7x+10)(x-3)=0
hay \(x\in\left\{-\dfrac{10}{7};3\right\}\)
d: \(\Leftrightarrow\dfrac{13}{2x^2+7x-6x-21}+\dfrac{1}{2x+7}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{\left(2x+7\right)}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow26x+91+x^2-9-12x-14=0\)
\(\Leftrightarrow x^2+14x+68=0\)
hay \(x\in\varnothing\)
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x - 17 = 2 x 17 x 5
=> X - 17 = 170
=> x = 187
49 - x = 21 x 63 + 37 x 3 x 7
=> 49 - x = 21( 63 + 37)
=> 49 - x = 2100
=> x = - 2051
2x + 3x = 15
=> 5x = 15
=> x = 3
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\Leftrightarrow\dfrac{7x+10}{x+1}\left(x^2-x-2-2x^2+3x+5\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(-x^2+2x+3\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\cdot\left(x^2-2x-3\right)=0\)
=>(7x+10)(x-3)=0
=>x=3 hoặc x=-10/7
b: \(\Leftrightarrow\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{2x+7}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow13\left(x+3\right)+x^2-9-12x-42=0\)
\(\Leftrightarrow x^2-12x-51+13x+39=0\)
\(\Leftrightarrow x^2+x-12=0\)
=>(x+4)(x-3)=0
=>x=-4
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Bài 1: tính nhanh
a. 579 + 468 + 421 - 467
= (579 + 421) + (468 - 467)
= 1000 + 1
= 1001
b. 53 . 39 + 47 . 39 - 53 . 21 - 47 . 21
= 39 (53 + 47 ) - 21 (53 - 47)
= 39 . 100 - 21 . 6 = 3900 -126
= 3774
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>(x-7)(x+3)=0
hay \(x\in\left\{7;-3\right\}\)
b: =>2x+7=0
hay x=-7/2
c: \(\Delta=50-4\cdot6\cdot2=50-48=2\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{5\sqrt{2}-\sqrt{2}}{12}=\dfrac{\sqrt{2}}{3}\\x_2=\dfrac{\sqrt{2}}{2}\end{matrix}\right.\)
350-x=49+2(3x-21)
49+2(3x-21)=350-x
2(3x-21)=350-x-49
2(3x-21)=301-x
6x-42=301-x
6x=301-x+42
343-x=6x
=>6x+x=343
=>7x=343
=>x=49
Hok tốt
K mk nha
350 - x = 49 + 2(3x - 21)
<=> 350 - x = 49 + 6x - 42
<=> 350 - 49 + 42 = 6x + x
<=> 343 = 7x
=> x = 49