2^3.17-2^3.14
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a,\(5.2^2\)\(-18:3^2\)
\(=5.4-18:9\)
\(=20-2\)
\(=18\)
b, \(\text{17.85+15.17-120}\)
\(=17.\left(85+15\right)\)\(-120\)
= \(17.100-120\)
\(=1700-120\)
\(=1580\)
c, \(2^3\)\(.17-2^3\)\(.14\)
= \(2^3\)\(.\left(17-14\right)\)
\(=8.3\)
\(=24\)
Hok tốt !
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Bài 1:
a: Ta có: 8,5<3,5x<15
mà x là số nguyên
nên \(3,5x\in\left\{10,5;14\right\}\)
hay \(x\in\left\{3;4\right\}\)
b: Ta có: \(\left(3-\dfrac{1}{3}x\right):2+1.5=3\)
=>(3-1/3x):2=1,5
=>3-1/3x=3
=>x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\dfrac{-3}{25}\cdot\dfrac{4}{17}\cdot\dfrac{5}{-3}\cdot\dfrac{17}{2}=\dfrac{4}{17}\cdot\dfrac{17}{2}\cdot\dfrac{3}{25}\cdot\dfrac{5}{3}=2\cdot\dfrac{1}{5}=\dfrac{2}{5}\)
b: \(=-\dfrac{8}{15}\cdot\dfrac{13}{16}\cdot\dfrac{30}{13}=\dfrac{-8}{15}\cdot\dfrac{15}{8}=-1\)
c: \(=\dfrac{3}{11}\left(\dfrac{2}{9}\cdot\dfrac{-8}{33}+\dfrac{7}{9}\right)=\dfrac{3}{11}\cdot\dfrac{215}{297}=\dfrac{2015}{1089}\)
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a)\(3.5^2-16:2^2\)
=\(3.25-16:4\)
=\(75-4=71\)
b)\(2^3.17-2^3.14\)
=\(8.17-8.14\)
\(=8\left(17-14\right)\)
\(=8.3=24\)
c)\(15.141+59.15\)
=\(15\left(141+59\right)\)
\(=15.200\)=3000
d)17.85+15.17-120
\(=17\left(85+15\right)-120\)
=\(17.100-120\)
=\(170-120=50\)
e)\(20+[30-\left(5-1\right)^2]\)
\(=20+[30-\left(4\right)^2]\)
\(=20+\left(30-16\right)\)
\(=20+14=34\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3.17+3.17+3.17+.....+3.17=17.(3+3+3+...3)(100 số hạng 3)
=7.3.100=21.100=2100
Bài này dễ mà em
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![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(2^3\cdot17-2^3\cdot14\)
\(=2^3\cdot\left(17-14\right)=2^3\cdot3=24\)
Đề như thế nay dúng ko :
23 . 17 - 23 . 14
hay
23.17 - 23.14