thực hiên phép tính: \(\left(4x^5y^2+2x^4y-6x^3y^2+3xy^4-y^5\right)\div2x^2+xy-y^2\)
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a: \(=3y^2-5x^2y^3-2y^2+3x^2y^3=y^2-2x^2y^3\)
b: \(=6x-y+2x^2+3y^2-2x^2+x=7x-y+3y^2\)
c: \(=x-y+4y^2-6xy+\dfrac{10x^2}{y}\)
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\(a.\left(9x^2y^3-15x^4y^4\right):3x^2y-\left(2-3x^2y\right)y^2\)
\(=3y^2-5x^2y^3-2y^2+3x^2y^3\)
\(=y^2-2x^2y^3\)
\(b.\left(6x^2-xy\right):x+\left(2x^3y+3xy^2\right):xy-\left(2x-1\right)x\)
\(=6x-y+2x^2+3y-2+x\)
\(=2x^2+7x+2y-2\)
\(c.\left(x^2-xy\right):x+\left(6x^2y^5-9x^3y^4+15x^4y^3\right):\dfrac{3}{2}x^2y^3\)
\(=x-y+4y^2-6xy+10x^2\)
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Bài 3:
3: \(6x\left(x-y\right)-9y^2+9xy\)
\(=6x\left(x-y\right)+9xy-9y^2\)
\(=6x\left(x-y\right)+9y\left(x-y\right)\)
\(=\left(x-y\right)\left(6x+9y\right)\)
\(=3\left(2x+3y\right)\left(x-y\right)\)
Bài 4:
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a) \(\left(x+3y\right)\left(2x^2y-6xy^2\right)\)
\(=x\left(2x^2y-6xy^2\right)+3y\left(2x^2y-6xy^2\right)\)
\(=2x^3y-6x^2y^2+6x^2y^2-18xy^3\)
\(=2x^3y-18xy^3\)
b) \(\left(6x^5y^2-9x^4y^3+15x^3y^4\right):3x^3y^2\)
\(=6x^5y^2:3x^3y^2-9x^4y^3:3x^3y^2+15x^3y^4:3x^3y^2\)
\(=2x^2-3xy+5y^2\)
c) \(\left(2x+3\right)^2+\left(2x+5\right)^2-2\left(2x+3\right)\left(2x+5\right)\)
\(=\left(2x+3-2x-5\right)^2\)
\(=\left(-2\right)^2=4\)
d) \(\left(y+3\right)^3-\left(3-y\right)^2-54y\)
\(=y^3+9y^2+27y+27-\left(x^2-6x+9\right)-54y\)
\(=y^3+9y^2-27y+27-x^2+6y-9\)
\(=y^3+9y^2-x^2-21y+18\)
Ta có: \(\frac{4x^5y^2+2x^4y-6x^3y^2+3xy^4-y^5}{2x^2+xy-y^2}\)
\(=\frac{y\left(4x^5y+2x^4-6x^3y+3xy^3-y^4\right)}{\left(2x-y\right)\left(x+y\right)}\)
Tính ra nữa được k ạ @@