(x-1)(x+5)(x+9)(x+3)=385
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\(x+2x+3x+...+9x+10x=385\)
\(x.\left(1+2+3+...+10\right)=385\)
\(55x=385\)
\(x=\frac{385}{55}\)
\(x=7\)
Vậy \(x=7\)
Tham khảo nhé~
x.1 + x.2 + x.3 + ... + x.9 + x.10 = 385
x. ( 1 + 2 + 4 + 5 + 6 + 7 + 8 + 9 + 10 ) = 385
x. 55 = 385
x = 385 : 55
x = 7
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1. 385 x 385+ 385 x 615 = 385 ( 385 + 615)
= 385 x 1000
= 385000
2a) 6 x (X + 7545) = 28542 x6
6X + 45270 = 171252
6X = 125982
x= 125982:6
x= 20997
b) (X : 4) x8 = 9 x 8
( X :4 ) x 8 = 72
X : 4 = 72 :8
X : 4 = 9
x = 9 x 4
X= 36\(\)
![](https://rs.olm.vn/images/avt/0.png?1311)
35 x 11 + 385 x 45 + 385 x 9 x 6 = 385 + 385 x 45 + 385 x 54 = 385 x (1 + 45 + 54) = 385 x 100 = 38 500
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b) \(-2\dfrac{2}{3}:x=1\dfrac{7}{9}:0.8\\ -\dfrac{8}{3}:x=\dfrac{16}{9}:\dfrac{4}{5}\\ -\dfrac{8}{3}:x=\dfrac{16}{9}.\dfrac{5}{4}\\ -\dfrac{8}{3}:x=\dfrac{20}{9}\\ x=-\dfrac{8}{3}:\dfrac{20}{9}\\ x=-\dfrac{8}{3}.\dfrac{9}{20}\\ x=-\dfrac{6}{5}\)
\(2\dfrac{2}{3}x+3\dfrac{3}{4}x=\dfrac{385}{24}\)
\(\dfrac{8}{3}x+\dfrac{15}{4}x=\dfrac{385}{24}\)
\(x\left(\dfrac{8}{3}+\dfrac{15}{4}\right)=\dfrac{385}{24}\)
\(x\left(\dfrac{32}{12}+\dfrac{45}{12}\right)=\dfrac{385}{24}\)
\(x\left(\dfrac{77}{12}\right)=\dfrac{385}{24}\)
\(x=\dfrac{385}{24}:\dfrac{77}{12}\)
\(x=\dfrac{385}{24}.\dfrac{12}{77}\)
<Bạn tự viết phép tính nha>
\(x=\dfrac{5}{2}\)
Vậy \(x=\dfrac{5}{2}\)
Chúc bn hk tốt!!
![](https://rs.olm.vn/images/avt/0.png?1311)
= 385 x 43 + [ 385 x ( 1 + 46 ) ]
= 385 x 43 + 385 x 47
= 385 x ( 43 + 47 )
= 385 x 90 = 34650
kb với mình đi
385 * 43 + ( 385 * 1 + 385 * 46 )=
=385 * ( 43 +46 +1 )
= 385 * 90
=34650
![](https://rs.olm.vn/images/avt/0.png?1311)
( x + x + x + ...+ x ) + ( 1 + 2 + 3 + ... + 10 ) = 385
x * 10 + 55 = 385
x * 10 = 385 - 55
x * 10 = 330
x = 330 : 10
x = 33
Vậy x = 33
(x + 1) + (x + 2) + (x + 3) +.....+(x + 10) = 385
=> 10x + (1 + 2 + 3 + 4 + ....+10) = 385
=> 10x + 55 = 385
=> 10x = 330
=> x = 33
![](https://rs.olm.vn/images/avt/0.png?1311)
x.1 + x.2 + x.3 + .....+ x.10 = 385
=> x.( 1+2+3+4+5+6+7+8+9+10 ) = 385
=> x.55 = 385
=> x = 385 : 55 = 7
Vậy x=7
#hoktot#
( x - 1 ) ( x + 9 ) ( x + 5 ) ( x + 3 ) = 385
⇔ ( x2 + 8x - 9 ) ( x2 + 8x + 15 ) = 385
Đặt t = x2 + 8x - 9, ta có :
t ( t + 24 ) = 385
⇔ t2 + 24t + 144 = 529
⇔ ( t + 12 )2 = 232
⇔ t = 11
⇒ x2 + 8x - 9 = 11
⇔ x2 + 8x - 20 = 0
⇔ ( x - 2 ) ( x + 10 ) = 0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+10=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-10\end{matrix}\right.\)