\(A=\frac{ac+bx+ax+bc}{ay+2bx+2ax+by}CM\)ko phụ thuộc AB
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{ac+bx+ax+bc}{ay+2bx+2ax+by}=\frac{a\left(c+x\right)+b\left(c+x\right)}{a\left(y+2x\right)+b\left(y+2x\right)}=\frac{\left(c+x\right)\left(a+b\right)}{\left(y+2x\right)\left(a+b\right)}\)
Do \(a\ne-b\Rightarrow a+b\ne0\Rightarrow\)\(A=\frac{c+x}{y+2x}\), giá trị không phụ thuộc vào a; b (đpcm)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) A = ax - ay - bx + by
A = a(x - y) - b(x - y)
A = (a - b)(x - y)
A = 1. (-2) = -2
B = 2ax + 2ay - 2bx - 2by
B = 2a(x + y) - 2b(x + y)
B = 2(x + y)(a - b)
B = 2. (-5).(-2) = 20
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(ab+ac=a.\left(b+c\right)\)
b) \(ab-ac+ad=a.\left(b-c+d\right)\)
c) \(ax-bx-cx-dx=x.\left(a-b-c-d\right)\)
d) \(a.\left(b+c\right)-d.\left(b+c\right)=ab+ac-db-dc=b.\left(a-d\right)+c.\left(a-d\right)=\left(a-d\right).\left(b+c\right)\)
e) \(ac-ad+bc-bd=a.\left(c-d\right)+b.\left(c-d\right)=\left(c-d\right).\left(a+b\right)\)
f) \(ax+by+bx+ay=a.\left(x+y\right)+b.\left(y+x\right)=\left(x+y\right).\left(a+b\right)\)
CHÚC BN HỌC TỐT!!!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
ab + ac = a(b + c)
ab - ac + ad = a(b - c + d)
ax - bx - cx + dx
=x(a - b - c + d)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(ay+by+ax+bx\)
\(=y\left(a+b\right)+x\left(a+b\right)\)
\(=\left(a+b\right)\left(x+y\right)\)
b) \(3xy-6y+2ax-4a\)
\(=3y\left(x-2\right)+2a\left(x-2\right)\)
\(=\left(x-2\right)\left(3y+2a\right)\)
c) sai đề ?
p/s: Trần Quỳnh Phương tên đẹp đấy nhưng lần sau nhớ viết đề cẩn thân hơn nhé!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2ax-bx+3cx-2a+b-3c\\ =x\left(2a-b+3c\right)-\left(2a-b+3c\right)\\ =\left(x-1\right)\left(2a-b+3c\right)\)
\(ax-bx-2cx-2a+2b+4c\\ =x\left(a-b-2c\right)-2\left(a-b-2c\right)\\ =\left(x-2\right)\left(a-b-2c\right)\)
\(3ax^2+3bx^2+ax+bx+5a+5b\\ =3x^2\left(a+b\right)+x\left(a+b\right)+5\left(a+b\right)\\ =\left(3x^2+x+5\right)\left(a+b\right)\)
\(ax^2-bx^2-2ax+2bx-3a+3b\\ =x^2\left(a-b\right)-2x\left(a-b\right)-3\left(a+b\right)\\ =\left(x^2-2x-3\right)\left(a+b\right)\\ =\left(x+1\right)\left(x-3\right)\left(a+b\right)\)
ĐK : \(y\ne2x,a\ne-b\)
\(A=\frac{ac+bx+ax+bc}{ay+2bx+2ax+by}\)
\(=\frac{\left(ac+ax\right)+\left(bx+bc\right)}{\left(ay+by\right)+\left(2ax+2bx\right)}\)
\(=\frac{a\left(c+x\right)+b\left(c+x\right)}{y\left(a+b\right)+2x\left(a+b\right)}\)
\(=\frac{\left(c+x\right)\left(a+b\right)}{\left(a+b\right)\left(y+2x\right)}\)
\(=\frac{c+x}{y+2x}\) không phụ thuộc vào \(a,b\) ( đpcm )