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a) \(5\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
b) \(25\left(x-4\right)=0\)
\(\Rightarrow x-4=0\)
\(\Rightarrow x=4\)
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
a) 5.(x-7)=0⇔x-7=0⇔x=7
b) 25(x-4)=0⇔x-4=0⇔x=4
c) (34-2x).(2x-6)=0
⇔ 34-2x=0 hoặc 2x-6=0
⇔2x=34 hoặc 2x=6
⇔ x=17 hoặc x=3
d) (2019-x).(3x-12)=0
⇔ 2019-x=0 hoặc 3x-12=0
⇔ x=2019 hoặc x=4
e) 57.(9x-27)=0
⇔ 9x-27=0
⇔ x=3
f) 25+(15-x)=30
⇔ 15-x=5
⇔ x=10
g) 43-(24-x)=20
⇔ 24-x=23
⇔ x=1
h) 2.(x-5)-17=25
⇔ 2(x-5)=42
⇔x-5=21
⇔ x=26
i) 3(x+7)-15=27
⇔ 3(x+7)=42
⇔ x+7=14
⇔ x=7
j) 15+4(x-2)=95
⇔ 4(x-2)=80
⇔ x-2=20
⇔ x=22
k) 20-(x+14)=5
⇔ x+14=15
⇔ x=1
l) 14+3(5-x)=27
⇔ 3(5-x)=13
⇔ 5-x=13/3
⇔ x=5-13/3
⇔ x=2/3
a) Ta có: \(14-\left(5-8\right)^3+\left(-3\right)\cdot5\)
\(=14+27-15=26\)
b) Ta có: \(-7\cdot15+7\cdot\left(-35\right)+\left(-1\right)^{2019}\)
\(=-7\left(15+35\right)-1=-350-1=-351\)
c) Ta có: \(-18\cdot32+\left(-18\right)\cdot45+77\cdot\left(-32\right)-77\cdot50\)
\(=-18\left(32+45\right)+77\left(-32-50\right)\)
\(=-18\cdot77+77\cdot\left(-82\right)=77\left(-18-82\right)=77\cdot\left(-100\right)=-7700\)
d) Ta có: \(104-4\cdot\left[-5\cdot8+\left(7-10\right)^3\right]\)
\(=104-4\left[-40-27\right]=104-4\cdot\left(-67\right)=104+268=372\)
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
a) 65 . ( - 19 ) + 19 . ( - 24 )
= - 65 . 19 + 19 . ( - 24 )
= ( - 65 + - 24 ) . 19
= - 89 . 19
= - 1691
b ) 45 - 15 : 3
= 45 - 5
= 40
c ) 15 - ( - 85 ) - ( - 70 ) + 15 + ( - 85 )
= 15 + 85 + 70 + 15 + ( - 85 )
= 15 + 15 + 85 + ( - 85 ) + 70
= 30 + [ 85 + ( -85 ) ] + 70
= 30 + 0 + 70
= 30 + 70
= 100
d) 737737 . 255 - 255255 . 737
= 737 . 1001 . 255 - 255 . 1001 . 737
= ( 737 . 255 - 737 . 255 ) . 1001
= 0 . 1001
= 0
NHỚ K CHO MK NHA
a) = (-1235) + (-456)
=-1691
b) 45 - 15:3
= 45 - 5
= 40
c) 15 - ( -85) - (-70) + 15 + (-85)
= 15 + 15 - (-85) - 85 -( -70)
= 30 - 0 - (-70)
= 100
d) =737.1001. 255 - 255.1001.737
= 0
Nhớ k cho mình nếu bạn thấy đúng nhé!
a, (-123) -|-13| +(-7)
= (-123) -13+(-7)
= -136 + (-7)
= -143
b, 35- (4.52 - 5.23) + 2019
= 35- (4. 25 - 5.8) + 2019
= 35- ( 100 - 40) + 2019
= 35 - 60 +2019
= -25 + 2019
= 1994
c, 75+ (-20) +(-30)
= 55 + (-30)
= 25
d, 135. 27- 27.35 +150
= 27.(135 - 35) +150
= 27. 100+ 150
= 2700 + 150
= 2850
e, (8-5)3 + 77 : 75 + 2019
= 33 +( 77 : 75 ) + 2019
= 33 +72 + 2019
= 27 + 49 + 2019
= 76 + 2019
= 2095
g, 737737. 255 - 255255. 737
= 737. 1001. 255 - 255. 1001. 737
=[( 737. 255) - (255. 737)] .1001
= 0. 1001
= 0
h, 45-|-15| : 3
= 45 - 15 : 3
= 45 - 5
= 40
f, 160 : {|-17| + [32 . 5-(14+ 211 : 28)]}
= 160 : { 17 +[ 9 . 5- (14 + 23)]}
= 160 : { 17 +[ 9 . 5- (14 + 8)]}
= 160 : [17 +( 9 . 5- 22)]
= 160 : [17 +( 45- 22)]
= 160 : ( 17 + 23)
= 160 : 40
= 4