1.Tính
( 10 - 9,34 ) + ( 10 - 9,66 )
12 - ( 12 - 9,36 )
38,52 + 0, 302 x 100 - 0,72
2.Tìm x
1 - ( 5\(\frac{3}{8}\)+ x - \(7\frac{5}{24}\)) : 16\(\frac{2}{3}\)= 0
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a, ( 10 + 10 ) - ( 9,34 + 9 , 66 )
= 20 - 19
= 1
\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)
\(=3-\left(-1\right)\)
\(=4\)
b) \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)
\(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)
\(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)
\(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)
\(=\frac{199}{16}:\left(12-2\right)\)
\(=\frac{199}{16}:10\)
\(=\frac{199}{160}\)
c) \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)
\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)
\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)
( 10 - 9,34) + (10 - 9,66) = 0,66 +0,34 =1
12 - (12 - 9,36)= 12 -2,64 = 9,36
**** cho mink nhé
1.
( 10 - 9,34 ) + ( 10 - 9,66 )
= 0,66 + 0,34
= 1
12 - ( 12 - 9,36 )
= 12 - 2,64
= 9,36
38,52 + 0,302 x 100 - 0,72
= 38,52 + 30,2 - 0,72
= 68,72 - 0,72
= 68
2.
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0+1=1\)
\(\left(x-\frac{151}{12}\right):\frac{50}{3}=1\)
\(x-\frac{151}{12}=1\times\frac{50}{3}\)
\(x-\frac{151}{12}=\frac{50}{3}\)
\(x=\frac{50}{3}+\frac{151}{12}\)
\(x=\frac{117}{4}\)
Bài 1
\(\left(10-9,34\right)+\left(10-9,66\right)\)
\(=0.66+0,34=1\)
\(12-\left(12-9,36\right)\)
\(=12-2.64=9,36\)
\(38,52+0,302.100-0,72\)
\(=38,52+30,2-0,72\)
\(=7.6\)
Bài 2
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)
\(\frac{43}{8}+x-\frac{173}{24}=\frac{3}{50}\)
\(\frac{43}{8}+x=\frac{3}{50}+\frac{173}{24}\)
\(\frac{43}{8}+x=\frac{4361}{600}\)
\(x=\frac{142}{75}\)( gửi lại bài 2 đã )