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14 tháng 8 2019

 TL:

\(4x^2-y^2+4x+1\)

\(=\left(2x-1\right)^2-y^2\)

\(=\left(2x-1+y\right)\left(2x-1-y\right)\)

14 tháng 8 2019

\(x^3-x+y^3-y\)

\(=\left(x+y\right)\left(x^2-xy+x^2\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2-xy+x^2-1\right)\)

12 tháng 10 2023

`x^2 -4x+4-y^2`

`=(x^2 -4x+4)-y^2`

`=(x-2)^2 -y^2`

`=(x-2-y)(x-2+y)`

`x^2+2xy+y^2-x-y`

`=(x^2+2xy+y^2) -(x+y)`

`=(x+y)^2 -(x+y)`

`=(x+y)(x+y-1)`

`x^2-2xy+y^2-9`

`=(x^2-2xy+y^2)-3^2`

`=(x-y)^2-3^3`

`=(x-y-3)(x-y+3)`

Tách ra đi cậu.

12 tháng 10 2023

https://hoc24.vn/cau-hoi/927x118.8505894378996

giúp mik với ạ

8 tháng 12 2023

Phân tích đa thức thành nhân tử

1: \(x^2-x-y^2-y\)

\(=\left(x^2-y^2\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-1\right)\)

2: \(x^2-y^2+x-y\)

\(=\left(x^2-y^2\right)+\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y\right)+\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y+1\right)\)

3: \(3x-3y+x^2-y^2\)

\(=\left(3x-3y\right)+\left(x^2-y^2\right)\)

\(=3\left(x-y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x-y\right)\left(x+y+3\right)\)

4: \(5x-5y+x^2-y^2\)

\(=\left(5x-5y\right)+\left(x^2-y^2\right)\)

\(=5\left(x-y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x-y\right)\left(5+x+y\right)\)

5: \(x^2-5x-y^2-5y\)

\(=\left(x^2-y^2\right)-\left(5x+5y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-5\right)\)

6: \(x^2-y^2+2x-2y\)

\(=\left(x^2-y^2\right)+\left(2x-2y\right)\)

\(=\left(x-y\right)\left(x+y\right)+2\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y+2\right)\)

7: \(x^2-4y^2+x+2y\)

\(=\left(x^2-4y^2\right)+\left(x+2y\right)\)

\(=\left(x+2y\right)\left(x-2y\right)+\left(x+2y\right)\)

\(=\left(x+2y\right)\left(x-2y+1\right)\)

8: \(x^2-y^2-2x-2y\)

\(=\left(x^2-y^2\right)-\left(2x+2y\right)\)

\(=\left(x-y\right)\left(x+y\right)-2\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-2\right)\)

9: \(x^2-4y^2+2x+4y\)

\(=\left(x^2-4y^2\right)+\left(2x+4y\right)\)

\(=\left(x-2y\right)\left(x+2y\right)+2\left(x+2y\right)\)

\(=\left(x+2y\right)\left(x-2y+2\right)\)

10: \(x\left(x-y\right)+x^2-y^2\)

\(=x\left(x-y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x-y\right)\left(x+x+y\right)\)

\(=\left(x-y\right)\left(2x+y\right)\)

11: \(x^2-y^2+10x-10y\)

\(=\left(x^2-y^2\right)+\left(10x-10y\right)\)
\(=\left(x-y\right)\left(x+y\right)+10\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y+10\right)\)

12: \(x^2-y^2+20x+20y\)

\(=\left(x^2-y^2\right)+\left(20x+20y\right)\)

\(=\left(x-y\right)\left(x+y\right)+20\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y+20\right)\)

13: \(4x^2-9y^2-4x-6y\)

\(=\left(4x^2-9y^2\right)-\left(4x+6y\right)\)

\(=\left(2x-3y\right)\left(2x+3y\right)-2\left(2x+3y\right)\)

\(=\left(2x+3y\right)\left(2x-3y-2\right)\)

14: \(x^3-y^3+7x^2-7y^2\)

\(=\left(x^3-y^3\right)+\left(7x^2-7y^2\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)+7\cdot\left(x^2-y^2\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)+7\left(x-y\right)\left(x+y\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2+7x+7y\right)\)

15: \(x^3+4x-\left(y^3+4y\right)\)

\(=x^3-y^3+4x-4y\)

\(=\left(x^3-y^3\right)+\left(4x-4y\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)+4\left(x-y\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2+4\right)\)

16: \(x^3+y^3+2x+2y\)

\(=\left(x^3+y^3\right)+\left(2x+2y\right)\)

\(=\left(x+y\right)\left(x^2-xy+y^2\right)+2\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2-xy+y^2+2\right)\)

17: \(x^3-y^3-2x^2y+2xy^2\)

\(=\left(x^3-y^3\right)-\left(2x^2y-2xy^2\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)-2xy\left(x-y\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2-2xy\right)\)

\(=\left(x-y\right)\left(x^2-xy+y^2\right)\)

18: \(x^3-4x^2+4x-xy^2\)

\(=x\left(x^2-4x+4-y^2\right)\)

\(=x\left[\left(x^2-4x+4\right)-y^2\right]\)

\(=x\left[\left(x-2\right)^2-y^2\right]\)

\(=x\left(x-2-y\right)\left(x-2+y\right)\)

8 tháng 12 2023

Phân tích đa thức thành nhân tử nha

26 tháng 10 2021

a: \(=\left(3-x\right)\left(x+1\right)\)

b: \(=3x\left(x-y\right)-5\left(x-y\right)\)

=(x-y)(3x-5)

c: \(=x\left(x-y\right)-10\left(x-y\right)\)

\(=\left(x-y\right)\left(x-10\right)\)

26 tháng 10 2021

a) \(=x\left(3-x\right)+\left(3-x\right)=\left(3-x\right)\left(x+3\right)\)

b) \(=3x\left(x-y\right)-5\left(x-y\right)=\left(x-y\right)\left(3x-5\right)\)

c) \(=x\left(x-y\right)-10\left(x-y\right)=\left(x-y\right)\left(x-10\right)\)

d) \(=\left(x+y\right)^2-16=\left(x+y-4\right)\left(x+y+4\right)\)

e) \(=\left(x-y\right)\left(x+y\right)-4\left(x+y\right)=\left(x+y\right)\left(x-y-4\right)\)

f) \(=9-\left(4x^2-4xy+y^2\right)=9-\left(2x-y\right)^2=\left(3-2x+y\right)\left(3+2x-y\right)\)

g) \(=y\left(y^2-2xy+x^2-y\right)\)

h) \(=x^2\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x^2-4\right)=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

i) \(=x\left(x-y\right)+\left(x-y\right)\left(x+y\right)=\left(x-y\right)\left(2x+y\right)\)

10 tháng 5 2017

Giải sách bài tập Toán 8 | Giải bài tập Sách bài tập Toán 8

13 tháng 11 2021

a) \(=6x^2y^2\left(6xy-7\right)\)

b) \(=3xy\left(x^3y+5x-6\right)\)

c) \(=\left(ax+ab\right)-\left(bx+x^2\right)=a\left(b+x\right)-x\left(b+x\right)=\left(a-x\right)\left(b+x\right)\)

d) \(=3\left(2x-1\right)-\left(2x-1\right)^2=\left(2x-1\right)\left(3-2x+1\right)=\left(2x-1\right)\left(4-2x\right)=2\left(2x-1\right)\left(2-x\right)\)

 

13 tháng 11 2021

\(a,=6x^2y^2\left(6xy-7\right)\\ b,=3xy\left(x^3y+5x-6\right)\\ c,=x\left(a-x\right)-b\left(a-x\right)=\left(x-b\right)\left(a-x\right)\\ d,=3\left(2x-1\right)-\left(2x-1\right)^2=\left(2x-1\right)\left(3-2x+1\right)=2\left(2-x\right)\left(2x-1\right)\)

1 tháng 11 2021

\(a,=x\left(x^2-10x+25\right)=x\left(x-5\right)^2\\ b,=y\left(x+y\right)-\left(x+y\right)=\left(y-1\right)\left(x+y\right)\\ c,=\left(x-5\right)^2\\ d,=\left(x-8\right)\left(x+8\right)\)

18 tháng 7 2019