27^16 . 16^9 và 12^18
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Le Thi My Duyen đừng lih tih, trog câu hỏi tương tự CỐ GẮNG LÊN BẠN NHÉ lm lih tih !!
1218 = 318 . 236
276 . 169 = 318 . 336
=> 1218 = 276 . 169
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\(12^{18}=4^{18}.3^{18}=\left(2^2\right)^{18}.3^{18}=2^{36}.3^{18}\)
\(27^{16}.16^9=\left(2^4\right)^9.\left(3^3\right)^{16}=2^{36}.3^{48}\)
\(\Rightarrow27^{16}.16^9>12^{18}\)
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\(\dfrac{3}{4}-\dfrac{3}{12}=\dfrac{3\times3}{4\times3}-\dfrac{3}{12}=\dfrac{9}{12}-\dfrac{3}{12}=\dfrac{9-3}{12}=\dfrac{6}{12}=\dfrac{1}{2}\\ \dfrac{16}{9}-\dfrac{18}{27}=\dfrac{16}{9}-\dfrac{2}{3}=\dfrac{16}{9}-\dfrac{2\times3}{3\times3}=\dfrac{16}{9}-\dfrac{6}{9}=\dfrac{16-6}{9}=\dfrac{10}{9}\)
9/12 - 3/12 = 3/12
48/27 - 18/27 = 30/27
Học tốt nha. Nhớ tick cho tui nha
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y + \(\dfrac{16}{9}\) = \(\dfrac{25}{9}\)
y = \(\dfrac{25}{9}\) - \(\dfrac{16}{9}\)
y = 1
ta có : y+\(\dfrac{4}{9}\)+\(\dfrac{8}{18}\)+\(\dfrac{12}{27}\)+\(\dfrac{16}{36}\)=\(\dfrac{25}{9}\)
⇒ y+\(\dfrac{16}{9}\)=\(\dfrac{25}{9}\)
⇒ y=\(\dfrac{25}{9}-\dfrac{16}{9}\)
⇒ y=1
Vậy y=1
Chúc bạn học tốt nha !