Question

[Nấm Lùn Đáng Yêu]

Bài 1: Tính

1/1×2 + 1/1×3 + 1/3×4 +••••+ 1/99×100

( 1/1×3 + 1/3×5 + •••• + 1/99×101) × X = 3/4

Giúp mink nhé Thank !!!

Answer 1

[Nguyễn Tấn Phát]

Ta có:

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)

\(=1-\frac{1}{100}\)

\(=\frac{99}{100}\)

Ta có: \(\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{99.101}\right).x=\frac{3}{4}\)

\(2.\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{99.101}\right).x=2.\frac{3}{4}\)

\(\left(\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{99.101}\right).x=\frac{3}{2}\)

\(\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{101}\right).x=\frac{3}{2}\)

\(\left(1-\frac{1}{101}\right).x=\frac{3}{2}\)

\(\frac{100}{101}.x=\frac{3}{2}\)

\(x=\frac{3}{2}:\frac{100}{101}\)

\(x=\frac{303}{200}\)